First you would see is there is a Greatest Common Factor. Then you would factor the difference of squares binomial. After factoring out the GCF, the square root of the first term is 'a' and the square root of the second term is 'b'. Once 'a' and 'b' are found, substitute them into the binomial factors (a + b)(a - b).
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To factor a trinomial square take the square roots of the end terms and join them with a plus sign if the middle term is preceded by a plus or with a minus if the middle term is preceded by a minus.
The difference of two squares (k2x2 - n2y2) is factorised as (kx+ny)(kx-ny).
Therefore, 9a-64b2 is factorised as (3√a+8b)(3√a-8b).
just like factoring any other trinomial.
It's not enough to copy the question off the test. If you don't tell us what the trinomial is, we can't factor it for you.
There is a formula for the difference of two squares. The sum of two squares doesn't factor.
(t - 15)(t + 3)
just make the trinomial easier to factor. ex -x2 + 3x + 4 ... most books don't teach you how to factor when a leading term is negative. ... so -1(x2- 3x- 4) ... now factor again ignoring the -1 -1(x - 4)(x + 1)