Find two numbers differing by 3 which multiply to 28.
4 and 7 will do.
(x + 7)(x - 4)
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-x(x2 - 2)(x2 + 3)
x2-3x+2.25 is the same as 4x2-12x+9 and is (2x-3)(2x-3) when factored
9x(x2+3x-10) * * * * * 9x3 + 27x2 - 90x = 9x(x2 + 3x - 10) = 9x(x + 5)(x - 2).
(3x + 5)(x2 - 2)
First take out -3x to make-3x(x2+11)If you're not using imaginary numbers, then you're done. Otherwise factor x2+11 using the sum of two squares rule.-3x(x-sqrt(11)i)(x+sqrt(11)i)