x2 + 3x - 40 = (x + 8)(x - 5)
If you mean: x2+3x+2 then it is (x+1)(x+2) when factored
If you factor x2 - 3x - 10, you'll get (x-5) (x+2). If your equation is x2 - 3x -10 = 0, then x = 5, and x = -2.
x2 + 3x - 28 = x2 + 7x - 4x - 28 = x(x + 7) - 4(x + 7) = (x + 7)(x - 4)
(x - 3)(x2 + 3x + 9)
x2-3x-28
If that's -3x, the answer is (x - 7)(x + 4) If that's +3x, the answer is (x + 7)(x - 4)
Find two numbers differing by 3 which multiply to 28. 4 and 7 will do. (x + 7)(x - 4)
x2 + 3x - 40 = (x + 8)(x - 5)
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
(x2 + 3x + 5)(x2 - 3x + 4)
(x-4) (x+7)
If you mean: x2+3x+2 then it is (x+1)(x+2) when factored
x2-3x-10 = (x+2)(x-5) when factored
If you factor x2 - 3x - 10, you'll get (x-5) (x+2). If your equation is x2 - 3x -10 = 0, then x = 5, and x = -2.
x2 + 3x - 18 = (x + 6)(x - 3)