75
379
There are three factor pairs for 75:factor pair = 75,1factor pair = 25,3factor pair = 15,5
75
1, 3, 5, 15, 25, 75: 1 x 75, 3 x 25, 5 x 15
75
75 = 375 / 5
Exactly 75 times !
21 5s
In the Rb atom, the electron configuration is [Kr]5s^1. This means there is 1 electron in the 5s sublevel of the Rb atom.
7
20
24
90
10
i think there are 18 digit 5s.
The answer is 525. The prime factorization for 35 is 7*5, and the one for 75 is 3*5*5.Take the 5s from 75, and the 3, and take 7 from 35. Multiply it to get 525!