zero
The colour series 3 and 4 of Callan are both available on DVD, but the monochrome series 1 and 2 are not available. Much of the first and second b&w series is 'missing, believed wiped' with the following episodes not available at all: Missing or incomplete episodes for programme CALLAN.Series 115.07.67 Goodbye Nobby Clarke (missing)22.07.67 The Death Of Robert E. Lee (missing)29.07.67 Goodness Burns Too Bright (missing)05.08.67 But He's A Lord, Mr. Callan (missing)Series 222.01.69 You're Under Starter's Orders (missing)19.02.69 Land Of Light And Peace (missing)26.02.69 Blackmailers Should Be Discouraged (missing)12.03.69 Jack-On-Top (missing)19.03.69 Once A Big Man, Always A Big Man (missing)26.03.69 The Running Dog (missing) Thirteen b&w episodes from Seasons 1 and 2 have survived, but the picture quality is extremely poor. Dedicated Callan viewers won't mind this, however, and the coloured series 3 and 4 are excellent.
i Think they should be because kids need them if a kid is sick the could use there ipod and video call one of there friends in class to get there home work and work there missing from class
DHT - Distributed Hash Table. A DHT problem stems from an incorrect hash - file corruption error. Look through the help for your P2P sharing system and it should direct you how to either ignore the problem (not recommended as that is how virus's are introduced) or correct the problem IF you have a client side hash problem.
i don't know but im having the same problem
It depends on what your problem is. If you are being bullied, then you should go to your parents, your teacher or an adult you know.
Zero.
Make sure that each polynomial is written is DESCENDING order. *Apex student*
Multiplication
There are two major problems in answering this question. The first problem is that there are infinitely polynomials of order 7 that will give these as the first seven numbers and any one of these could be "the" rule. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one. The second problem is that you have not specified where, in the sequence the missing number should have been. If the missing number was the last, the simplest polynomial rule of order 6 ist(n) = (-36*n^6 + 854*n^5 - 7945*n^4 + 36680*n^3 - 87299*n^2 + 99386*n - 39600)/120 for n = 1, 2, 3, ... and, accordingly the next number is -396. If missing number was the first, the simplest polynomial rule of order 6 is different and the first number is 330.
Division by a number is the same as multiplication by its reciprocal. That is, n / a = n * (1/a) and as you should know, (1/a) is the reciprocal of a.
The problem would not end
I suppose you mean factoring the polynomial. You can check by multiplying the factors - the result should be the original polynomial.
- a problem in NP means that it can be solved in polynomial time with a non-deterministic turing machine - a problem that is NP-hard means that all problems in NP are "easier" than this problem - a problem that is NP-complete means that it is in NP and it is NP-hard example - Hamiltonian path in a graph: The problem is: given a graph as input, an algorithm must say whether there is a hamiltonian path in it or not. in NP: here is an algorithm that works in polynomial time on a non-deterministic turing machine: guess a path in the graph. Check that it is really a hamiltonian path. NP-hard: we use reduction from a problem that is NP-comlete (SAT for example). Given an input for the other problem we construct a graph for the hamiltonian-path problem. The graph should have a path iff the original problem should return "true". Therefore, if there is an algorithm that executes in polynomial time, we solve all the problems in NP in polynomial time.j
false
Take the answer of the division problem and multiply it by one of the numbers. It should equal the OTHER number. a/b = c c * b = a OR c * a = b
the solutions to this equation are -1,+1 and -3. you can solve this equation by using the polynomial long division method. we basically want to factorize this and polynomial and equate its factors to zero and obtain the roots of the equation. By hit and trial , it clear that x=1 i.e is a root of this equation. So (x-1) should be a factor of the given polynomial (LHS). Divide the polynomial by x-1 using long division method and you will get the quotient as x2+4x+3 and remainder would be 0 ( it should be 0 as we are dividing the polynomial with its factor. Eg when 8 is divided by any of its factor like 4,2 .. remainder is always zero ) Now, we can write the given polynomial as product of its factors as x3+3x2-x-3 = (x-1)(x2+4x+3) =(x-1)(x+1)(x+3) [by splitting middle term method] so the solutions for the given polynomial are obtained when RHS = 0, Hence x=-1 , X = +1, x=-3 are the solutions for this equation.
You could divide the answer into the larger number of the problem. The answer should be the remaining number (multiplicand).