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No. It doesn't end in a 5 or 0.

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11y ago
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8y ago

No, 16 divided by 5 is 3.2

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7y ago

16 is divisible by 1, 2, 4, 8, 16.

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Q: Is 16 divisible by 5
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Related questions

Is 1735 divisible by 3?

No; 1+7+3+5= 16 16 isn't divisible by 3.


What number is a paliindrome divisible by 5 and it's sum is divisible by 8?

if Divisible by 5 = ends in 0 or 5 if Palindrome = spelled the same forwards as backwards then number begins and ends with either 0 or 5 5_5, or 0_0 Sum is divisible by 8 5+5=10 16=divisible by 8 565


Is 5 divisible by 80?

No, 80 is bigger than 5.


What number is divisible by 3 15 5 and 7 but is not divisible by 16 10 19 12 and 6?

105


Is 3058 divisible by 6?

No. To be divisible by 6, a number must be even (divisible by 2) and divisible by 3. Although 3058 is even, it is not divisible by 3 since 3+0+5+8 = 16 which is not divisible by 3. Thus is it not divisible by 6.


What is the greatest 5 digit number that is a multiple of 16 and not divisible by 6?

99968


What number is 745 divisible by?

To determine what number 745 is divisible by, you need to check for divisibility rules of different numbers. 745 is not divisible by 2 because it is not even. It is not divisible by 3 because the sum of its digits (7+4+5 = 16) is not a multiple of 3. It is not divisible by 5 because it does not end in 0 or 5. However, 745 is divisible by 5 because the last digit is 5.


Is 160 divisible by 10 by 2 by 5?

160 is divisible by all three numbers, 10, 2, and 5. 160 / 10 = 16 160 / 2 = 80 160 / 5 = 32


What is 22480 divisible by?

22480 = 281 x 5 x 16 x 1. And 16 is 2^4, so you can have any combination of these factors that 22480 is divisible by [2 x 2 x 5 = 20, for example].


Is 745 divisible by 2 3 5 9 or 10?

Out of that list, just 5. ------------------------------------------------ To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8} The last digit is 5 which is not even (it is odd), so 745 is not divisible by 2 To be divisible by 3 the sum of the digits must also be divisible by 3; if the summing is repeated until a single digit remains, then the original number is only divisible by 3 if this single digit is divisible by 3, ie it is one of {3, 6, 9} 745 → 7 + 4 + 5 = 16 16 + 1 + 6 = 7 7 is not divisible by 3 (it is not one of {3, 6, 9}), so 745 is not divisible by 3 To be divisible by 5, the last digit must be 0 or 5 The last digit of 745 is 5 which is one of {0, 5}, so 745 is divisible by 5 To be divisible by 9 the sum of the digits must also be divisible by 9; if the summing is repeated until a single digit remains, then the original number is only divisible by 9 if this single digit is 9 (otherwise this single digit gives the remainder when the original number is divided by 9) 745 + 7 + 4 + 5 = 16 16 → 1 + 6 = 7 7 is not 9, so 745 is not divisible by 9 (the remainder is 7) To be divisible by 10 the last digit must be 0 The last digit of 745 is 5 which is not 0, so 745 is not divisible by 10. 745 is not divisible by 2, 3, 9, 10 745 is divisible by 5.


Is 16 divisible by 10?

Nope. 16 is divisible by 1, 2, 4, 8, 16.


Which number is a composite number 5 7 13 and 16?

16, it is divisible by 2, 4,8 in addtion to itself and 1