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No. It doesn't end in a 5 or 0.
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What is 22480 divisible by?
22480 = 281 x 5 x 16 x 1. And 16 is 2^4, so you can have any combination of these factors that 22480 is divisible by [2 x 2 x 5 = 20, for example].
Explain Why is 5 divisible by 1260?
5 is not divisible by 1260. 1260 is divisible by 5 because 1260 is a multiple of 5.
What is 625 divisible by?
625 Is divisible by 5
Is 73689 divisible by 5?
No, only numbers that end in 5 or 0 are divisible by 5.
Are all numbers divisible by 5 also divisible by 10?
no because 5,15,25,35,45,55,65,75,85,95,105...are not divisible by 10.10,20,30,40,50,60,70,80,90,100 are divisible by 10 and 5
Is 1735 divisible by 3?
No; 1+7+3+5= 16 16 isn't divisible by 3.
What number is a paliindrome divisible by 5 and it's sum is divisible by 8?
if Divisible by 5 = ends in 0 or 5 if Palindrome = spelled the same forwards as backwards then number begins and ends with either 0 or 5 5_5, or 0_0 Sum is divisible by 8 5+5=10 16=divisible by 8 565
Is 5 divisible by 80?
No, 80 is bigger than 5.
What number is divisible by 3 15 5 and 7 but is not divisible by 16 10 19 12 and 6?
105
Is 3058 divisible by 6?
No. To be divisible by 6, a number must be even (divisible by 2) and divisible by 3. Although 3058 is even, it is not divisible by 3 since 3+0+5+8 = 16 which is not divisible by 3. Thus is it not divisible by 6.
What is the greatest 5 digit number that is a multiple of 16 and not divisible by 6?
99968
Is 160 divisible by 10 by 2 by 5?
160 is divisible by all three numbers, 10, 2, and 5. 160 / 10 = 16 160 / 2 = 80 160 / 5 = 32
What is 22480 divisible by?
22480 = 281 x 5 x 16 x 1. And 16 is 2^4, so you can have any combination of these factors that 22480 is divisible by [2 x 2 x 5 = 20, for example].
Is 745 divisible by 2 3 5 9 or 10?
Out of that list, just 5. ------------------------------------------------ To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8} The last digit is 5 which is not even (it is odd), so 745 is not divisible by 2 To be divisible by 3 the sum of the digits must also be divisible by 3; if the summing is repeated until a single digit remains, then the original number is only divisible by 3 if this single digit is divisible by 3, ie it is one of {3, 6, 9} 745 → 7 + 4 + 5 = 16 16 + 1 + 6 = 7 7 is not divisible by 3 (it is not one of {3, 6, 9}), so 745 is not divisible by 3 To be divisible by 5, the last digit must be 0 or 5 The last digit of 745 is 5 which is one of {0, 5}, so 745 is divisible by 5 To be divisible by 9 the sum of the digits must also be divisible by 9; if the summing is repeated until a single digit remains, then the original number is only divisible by 9 if this single digit is 9 (otherwise this single digit gives the remainder when the original number is divided by 9) 745 + 7 + 4 + 5 = 16 16 → 1 + 6 = 7 7 is not 9, so 745 is not divisible by 9 (the remainder is 7) To be divisible by 10 the last digit must be 0 The last digit of 745 is 5 which is not 0, so 745 is not divisible by 10. 745 is not divisible by 2, 3, 9, 10 745 is divisible by 5.
Is 16 divisible by 10?
Nope. 16 is divisible by 1, 2, 4, 8, 16.
Which number is a composite number 5 7 13 and 16?
16, it is divisible by 2, 4,8 in addtion to itself and 1
Is 21733 divisible by 3?
No, it is not divisible by 3. Add all the digits of 21733, we will get 16 & 16 is not divisible by 3.
