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Every palindrome with an even number of digits is divisible by 11. The easiest way to see this is to recall the divisibility rule by 11: if a number X is written as ABCDEFG... (here A,B,C, ... are digits), then it's divisible by 11 if and only if the sum A-B+C-D+E-F+G-... is divisible by 11. In a palindrome with an even number of digits, each digit will appear in an odd position and in an even position, so when we calculate this sum, it will be added once and subtracted once, canceling. Since all the digits cancel, the sum A-B+C-D+... will be 0, which is divisible by 11. So the original number ABCD....DCBA was also divisible by 11.
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Is every number a factor of 1?
1 is a factor of every number.
Is Every prime number is a factor of 1.?
Nope.... 1 is a factor of every prime number !
Which number is greatest factor of every number?
The greatest factor of any number is the number itself. There is no integer that is the greatest factor of every number. One is a factor of every number. One is the GCF of co-prime numbers.
Why is 1 always a factor of any number?
because 1 x (every number) = (every number) and that makes 1 a factor of (every number)
Is it true that every number has a 0.5 factor?
No because factors are whole numbers but every whole number except zero has 1 as a factor.
