The common factors of 486 and 6 are 1, 2, 3, and 6.
The factors of 2 are: 1, 2 The factors of 6 are: 1, 2, 3, 6 The common factors are: 1, 2
The factors of 6 are: 1, 2, 3, 6.The factors of 16 are: 1, 2, 4, 8, 16.The common factors are: 1, 2
The common factors of 6 and 27 are 1 and 3.
The common factors of 6 and 15 is 1 and 3 that's all
12x - 2x = 10
Yes. Factors of 12x2: 1, 2, 3, 4, 6, 12, x, x2, and the products of all of their pairs. Factors of 14xy: 1, 2, 7, x, y, and the products of all of their pairs. Common factors: 2, x, 2x GCF: 2x
2.2.x.x.
(2x - 3)(x + 2)
I assume you mean factors for 4x2+10x+6.(2x+3)(2x+2).
common it's very easy !!2x + 3 = 92x = 6x = 6/2x = 3
2x² - 18 Looking at it, you know that the first factors in each set are 2x and x. (2x ± ?) (x ± ?) Then guess and check to find 2 factors that when multipled together equal -18, but when plugged into the equation make the original statement true. In this case 6 and 3, however one or the other needs to be negative. (2x + 6)(x - 3) OR (2x - 6)(x + 3) Multiply it out to check your answer: (2x + 6)(x - 3) = 2x² - 6x + 6x - 18 2x² - 6x + 6x - 18 = 2x² - 18 You would get the same result with (2x - 6)(x + 3)
The common factors of 6 are 1, 2, 3, and 6.
The common factors of 6 and 18 are 1, 2, 3, and 6
Common factors of 6 and 18 are 1,2,3,6.
If that's + 6, that factors to (3x - 2)(2x - 3)
-2x-6= -2x-6Another answer:-2x-6 = 2x+6-2x-2x = 6+6-4x = 12x = -3