The factors of (11x) are (1), (11), (x), and (11x). For (55), the factors are (1), (5), (11), and (55). Both expressions share the common factors (1), (11), and their respective constants. Thus, (11) is a common factor of both (11x) and (55).
The common factors of 15 and 55 are: 1 and 5
Factors of 55 are: 1, 5, 11, and 55.Factors of 100 are: 1, 2, 4, 5, 10, 20, 25, 50, and 100.Common factors of 55 and 100 are: 1 and 5.
11 is a prime number. Its only factors are one and itself.
The common factors of 44 and 55 are: 1 and 11
1, 5, 11, 55
x=55/-11=-5
If that's - 11x - 20, the answer is (4x + 5)(x - 4). If that's + 11x + 20, it gets ugly in a hurry.
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
-4x2 + 11x - 6 factors to: (-4x + 3) (x - 2)
If you mean x2+11x+24 then it is (x+3)(x+8) when factored
If you mean: (3x+1) and (2x+3) are factors of 6xsquared+11x+3 then yes they are
If you meant to write -x2 - 11x + 26, that factors to -(x - 2)(x + 13)
3x2 - 11x - 4 = (x-4)(3 x + 1)
(x + 15)(x - 4)
The factors of 55 are 1, 5, 11, 55.
6 + 11x - 60 =6 - 60 + 11x = -54 + 11x = 11x -54
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)