If that's - 11x - 20, the answer is (4x + 5)(x - 4). If that's + 11x + 20, it gets ugly in a hurry.
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
If you mean x2+11x+24 then it is (x+3)(x+8) when factored
(3x + 1)(x - 4)
(2x - 3)(2x + 3)(4x2 + 9)
To simplify the expression (3x + 4(2x + 5)), first distribute the 4: [ 3x + 8x + 20 = 11x + 20. ] Now, simplify the second expression (6x + 5x + 5): [ 11x + 5. ] Since (11x + 20) is not equal to (11x + 5), Lauren is incorrect; the two expressions are not equivalent.
4x2-11x-20=(x-4)(4x+5) 4x2-11x-20=4x2+ax+bx-20ab = 4*-20 = -80a+b = -11a = -16, b = 54x2-11x-20=4x2-16x+5x-204x2-16x+5x-20=4x(x-4)+5(x-4)4x(x-4)+5(x-4)=(x-4)(4x+5)Factorised, 4x2-11x-20=(x-4)(4x+5)
-4x2 + 11x - 6 factors to: (-4x + 3) (x - 2)
if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)
It is: -4x^2 +11x -6 equals (-4x+3)(x-2) when factored
4x^2 - 11x + 6 = 0 (4x - 3)(x - 2) x = 3/4, 2
The factors of (11x) are (1), (11), (x), and (11x). For (55), the factors are (1), (5), (11), and (55). Both expressions share the common factors (1), (11), and their respective constants. Thus, (11) is a common factor of both (11x) and (55).
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
By using the quadratic equation formula: (4x+1)(x-3) = 0
Solution: x = 1/4 and x = -3.
4x2-11X=7 ARRANGE IN STANDARD FORM
-11x=22011x=-220x=-220/11=-20
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0