x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
If you mean x2+11x+24 then it is (x+3)(x+8) when factored
(3x + 1)(x - 4)
(2x - 3)(2x + 3)(4x2 + 9)
Assuming the missing signs are pluses, that factors to (2x + 5)(2x + 5)
4x2-11x-20=(x-4)(4x+5) 4x2-11x-20=4x2+ax+bx-20ab = 4*-20 = -80a+b = -11a = -16, b = 54x2-11x-20=4x2-16x+5x-204x2-16x+5x-20=4x(x-4)+5(x-4)4x(x-4)+5(x-4)=(x-4)(4x+5)Factorised, 4x2-11x-20=(x-4)(4x+5)
-4x2 + 11x - 6 factors to: (-4x + 3) (x - 2)
if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)
It is: -4x^2 +11x -6 equals (-4x+3)(x-2) when factored
4x^2 - 11x + 6 = 0 (4x - 3)(x - 2) x = 3/4, 2
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
4x2-11X=7 ARRANGE IN STANDARD FORM
By using the quadratic equation formula: (4x+1)(x-3) = 0
Solution: x = 1/4 and x = -3.
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
-11x=22011x=-220x=-220/11=-20
11x + 8 = 8x + 20 3x + 8 = 20 3x = 12 x = 4