If that's - 11x - 20, the answer is (4x + 5)(x - 4). If that's + 11x + 20, it gets ugly in a hurry.
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0
If you mean x2+11x+24 then it is (x+3)(x+8) when factored
(3x + 1)(x - 4)
(2x - 3)(2x + 3)(4x2 + 9)
Assuming the missing signs are pluses, that factors to (2x + 5)(2x + 5)
4x2-11x-20=(x-4)(4x+5) 4x2-11x-20=4x2+ax+bx-20ab = 4*-20 = -80a+b = -11a = -16, b = 54x2-11x-20=4x2-16x+5x-204x2-16x+5x-20=4x(x-4)+5(x-4)4x(x-4)+5(x-4)=(x-4)(4x+5)Factorised, 4x2-11x-20=(x-4)(4x+5)
-4x2 + 11x - 6 factors to: (-4x + 3) (x - 2)
if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)
It is: -4x^2 +11x -6 equals (-4x+3)(x-2) when factored
4x^2 - 11x + 6 = 0 (4x - 3)(x - 2) x = 3/4, 2
The factors of (11x) are (1), (11), (x), and (11x). For (55), the factors are (1), (5), (11), and (55). Both expressions share the common factors (1), (11), and their respective constants. Thus, (11) is a common factor of both (11x) and (55).
4x2+3x+6+5x+3x+6 = 4x2+11x+12 when simplified
Solution: x = 1/4 and x = -3.
4x2-11X=7 ARRANGE IN STANDARD FORM
By using the quadratic equation formula: (4x+1)(x-3) = 0
-11x=22011x=-220x=-220/11=-20
x2 = -11x - 10 x2 + 11x + 10 = 0 (x + 1)(x + 10) = 0