(3x - 2)(5x + 6)
325 is a triangle number. The exponents in the prime factorization are 2 and 1. Adding one to each and multiplying we get (2+1) (1+1)= 3x2 =6 Therefore 325 has exactly 6 factors
x(6x - 11)
66x^3 - 36x^2 = 6x^2(11x - 6) 55x - 30 = 5(11x - 6) 66x^3 - 36x^2 + 55x - 30 = (6x^2 + 5)(11x - 6)
If that's 3x2 - 7x + 4, the answer is (3x - 4)(x - 1)
If you set your equation to equal 7, then you can move 7 to the other side of the equation, and solve for x. This/these values will always result in 7. e.g. 3x2+11x+6=7 3x2+11x+6-7=7-7 3x2+11x-1=0 Factor using the quadratic formula and solve for x.
-4x2 + 11x - 6 factors to: (-4x + 3) (x - 2)
6= 3x2 2x3
6 + 11x - 60 =6 - 60 + 11x = -54 + 11x = 11x -54
(3x - 2)(5x + 6)
3x2-y=6 3x2-y=6
Prime factors of 6: 3x2 9: 3^2 Answer is 3
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
11x = 8x-6.............. 11x-8x = -6................... 3x= -6 x = -2
Prime factors of 5 = 5 Prime factors of 6 = 3x2 Thus LCM = 3x2x5 =30 Simple, Year 6 stuff.
so one way to do this is 24 divided by 2=12 so 12 and 2 are factors then 12 divided by 2=6 so 6 is a factor then 6= 3x2 so 3 is a factor also. 24, 6 12, 3 and 2 are the factors
2x + 6 + 9x = 39 11x + 6 = 39 11x = 39 - 6 11x = 33 x = 3