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What are the factors of the quadratic trinomial 8x2 plus 2x-1?
Wiki User
∙ 13y ago
8X^2 + 2X - 1 = 0
need quadratic formula
-b +/- sqrt(b^2-4ac)/2a
a = 8
b = 2
c = -1
-2 +/- sqrt(2^2 -4(8)(-1))/2(8)
-2 +/- sqrt(4 + 32)/16
-2 +/- sqrt(36)/16
(-2 +/- 6)/16
X = 1/4
X = -1/2
My TI-84 confirms this answer
Wiki User
∙ 13y ago
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What is the greatest common factor of 5 and 21?
The greatest common factor of 5 and 21 is 1
Prove that the trace of a matrix A is equal to the sum of its eigenvalues?
Given a matrix A=([a,b],[c,d]), the trace of A is a+d, and the det of A is ad-bc.By using the characteristic equation, and representing the eigenvalues with x, we have the equationx2-(a+d)x+(ad-bc)=0Which, using the formula for quadratic equations, gives us the eigenvalues as,x1=[(a+d)+√((a+d)2-4(ad-bc))]/2x2=[(a+d)-√((a+d)2-4(ad-bc))]/2now by adding the two eigenvalues together we get:x1+x2=(a+d)/2+[√((a+d)2-4(ad-bc))]/2+ (a+d)/2-[√((a+d)2-4(ad-bc))]/2The square roots cancel each other out being the same value with opposite signs, leaving us with:x1+x2=(a+d)/2+(a+d)/2x1+x2= 2(a+d)/2x1+x2=(a+d)x1+x2=trace(A)Q.E.D.General proofThe above answer only works for 2x2 matrices. I'm going to answer it for nxn matrices. (Not mxn; the question only makes sense when the matrix is square.) The proof uses the following ingredients:(1) Every nxn matrix is conjugate to an upper-triangular matrix(2) If A is upper-triangular, then tr(A) is the sum of the eigenvalues of A(3) If A and B are conjugate, then tr(A) = tr(B)(4) If A and B are conjugate, then A and B have the same characteristic polynomial (and hence the same sum-of-eigenvalues)If these are all true, then we can do the following: Given a matrix A, find an upper-triangular matrix U conjugate to A; then (letting s(A) denote the sum of the eigenvalues of A) s(A) = s(U) = tr(U) = tr(A).Now to prove (1), (2), (3) and (4):(1) This is an inductive process. First you prove that your matrix is conjugate to one with a 0 in the bottom-left corner. Then you prove that this, in turn, is conjugate to one with 0s at the bottom-left and the one above it. And so on. Eventually you get a matrix with no nonzero entries below the leading diagonal, i.e. an upper-triangular matrix.(2) Suppose A is upper-triangular, with elements a1, a2, ... , an along the leading diagonal. Let f(t) be the characteristic polynomial of A. So f(t) = det(tI-A). Note that tI-A is also upper-triangular. Therefore its determinant is simply the product of the elements in its leading diagonal. So f(t) = det(tI-A) = (t-a1) * ... * (t-an). And its eigenvalues are a1, ... , an. So the sum of the eigenvalues is a1 + ... + an, which is the sum of the diagonal elements in A.(3) This is best proved using Summation Convention. Summation convention is a strange but rather useful trick. Basically, the calculations I've written below aren't true as they're written. For each expression, you need to sum over all possible values of the subscripts. For example, where it says b_ii, it really means b11 + b22 + ... + bnn. Where it says bil deltali, it means (b11 delta11 + ... + b1n deltan1) + ... + (bn1 delta1n + ... + bnn deltann). Oh, and deltakj=1 if k=j, and 0 otherwise.Suppose B = PAP-1. Let's say the element in row j and column k of A is ajk. Similarly, say the (i,j) element of P is pij, the (k,l) element of P-1 is p*kl, and the (i,l) element of B is bil. Then:bil = pij ajk p*klAnd the trace of B is given by:tr(B) = bii= bil deltali= p*kl deltali pij ajk= p*kl plj ajk= deltakj ajk (since p and p* are inverses)= ajj= tr(A)(4) Again, suppose B = PAP-1. Then, for any scalar t, we have tI-B = P(tI-A)P-1. Hence det(tI-B) = det(P).det(tI-A).det(P-1). Since det(P).det(P-1)=det(PP-1)=det(I)=1, we have det(tI-B) = det(tI-A).
What are all the glee songs and who sings them?
Add on if you can!Here are some:Don't Stop BelievinSinging in the Rain / UmbrellaToxicForget You (Gwyneth Paltrow sang this on glee)Poker FaceTeenage DreamDon't Rain on my ParadeFaithfullyMy Life Would Suck Without YouOver the RainbowAnyway You Want It / Lovin' Touchin' SqueezinBad RomanceI Dreamed a DreamTrue ColorsMarry YouI'll Stand By YouBethThriller / Heads Will RollTotal Eclipse of the HeartBohemian RhapsodyTo Stir With LoveGives You Hell
2x1 plus 3x2 plus 7x3 equals 12?
No. 7*3, alone, is bigger than 12.
Maxz equals 2x1 plus 2x2 stc 5x1 plus 3x2 equals 8 x1 plus 2x2 equals 4 x1 x2 equals 0 and integerssolve by ipp?
3
What decimal is represented by this expanded form 3x1000 plus 6x100 plus 1x10 plus 2x110 plus 1x11000?
3x1000 + 6x100 + 1x10 + 2x1/10 + 1x1/1000 = 3000 + 600 + 10 + 0.2 + 0.001 = 3610.201
2x1?
2
How do you do 22.056 in expanded form?
22 + .056
1+1=2x1?
True
What is the name of the following math law 2 x 1 3 2x1 2x3?
2x (1+3)=(2x1+(2x3)
What are the factor multiplications for2?
1x2 2x1
What is 2 times1?
2x1=2
What is 2 one fourth plus 1one half?
2x1/4 +1/2= 2/4 + 1/2= 1/2+1/2 =2/2 =1
What is the degree of the polynomial 2x plus 5?
The degree of the polynomial 2x + 5 is 1. The highest power of x is x1, i.e. 2x1 + 5x0, hence the designation of first degree.
What is expanded form for 32?
( 3x10) + ( 2x1) = 32
