12x2+13x-35 = (4x-5)(3x+7)
12x2 + 13x- 35 let's find two factors of -420 (12*-35) whose sum is 13, which are 28 and -15
(12x + 28)(12x - 15) now simplify by 4 and 3
(3x + 7)(4x - 5)
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Factors of 12 and 35 which can equal 13 are 3/4 and 5/7 so:
(3x - 7)(4x + 5) assuming the sign of 35 in your equation is "-".
(10x + 1)(x + 10)
(3x - 4)(x - 1)
That's not a trinomial, but it factors to x(x + 19)
I think that wants to be 16x2 - 40xy + 25y2 That factors to (4x - 5y)(4x - 5y) or (4x - 5y)2
That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-615 plus or minus 15 times the square root of 3281) divided by 2. x = 122.10010474859058 x = -737.10010474859058