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x2 + 12x2 + 35 = 13x2 + 35 which cannot be factorised in any sensible way.

Q: What is the factorization of the trinomial x2 plus 12x2 plus 35?

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Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).

Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored

No.

If you mean x^2 -12x+35 then it is a quadratic expression which can be factored in the form of (x-7)(x-5)

8x2+6x-35 = (2x+5)(4x-7) when factored

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x3 - 12x2 + 35x = x(x2 - 12x + 35) = x(x - 5)(x - 7)

Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).

12x2-x-35 = (4x-7)(3x+5)

Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored

x3 - 12x2 + 35x = x (x2 - 12x + 35) = x (x - 7) (x - 5)

12x2+13x-35 = (4x-5)(3x+7) 12x2 + 13x- 35 let's find two factors of -420 (12*-35) whose sum is 13, which are 28 and -15 (12x + 28)(12x - 15) now simplify by 4 and 3 (3x + 7)(4x - 5)

No.

It is (7x+5)(2x-7) when factored

(4x-7)(3x+5) You can get this by using the formula method to find the two roots of the polynomial set equal to 0. Call them p and q. Then the answer is 12(x-p)(x-q) because you need to get the multiplier of x2 to be 12.

(x + 4)(3x + 35)

If you mean x^2 -12x+35 then it is a quadratic expression which can be factored in the form of (x-7)(x-5)

No.