I could factorize : (3 + x) (17 + 3 x) But have no idea about the next part...
(5x + 6)(x + 4)
The product is 78
1 x 78, 2 x 39, 3 x 26, 6 x 13.
LCM of 6 16 and 26 = 624 prime factorization of: 6 -= 2 -------------x 3 16 = 2 x 2 x 2 x 2 26 = 2 -----------------x13 ================= LCM=2 x 2 x 2 x 2 x 3 x 13 = 624
26x-4 = 25 +4 +4 26x = 29 x= 29/26 or 1.115...
26x = 156 Divide both sides of the equation by 26 to find the value of x: x = 6
26x + 9 = 699Subtract 9 from each side:26x = 690Divide each side by 26 :x = 690/26 = 26 and 14/690 = 26 and 7/345 = 26.5385 (rounded)
33.8=.26x x = 130
Call the unknown integer x. Then, from the problem statement, x - 3/x = 26/3, or:x2 - 3 = 26x/3; or x2 - (26/3)x - 3 = 0x = 9
The x-axis is y = 0 → y = 8x² - 26x + 15 → 0 = 8x² - 26x + 15 = (4x - 3)(2x - 5) So 4x - 3 = 0 → 4x = 3 → x = ¾ = 0.75 or 2x -5 = 0 → 2x = 5 → x = 2½ = 2.5 The y-axis is x = 0 → y = 8x² - 26x + 15 = 8 × 0² - 26 × 0 + 15 = 15 → The points of contact with the x- and y- axes of y = 8x² - 26x + 15 are: (0.75, 0), (2.5, 0), (0, 15)
x2 + 26x + 48 = (x + 24)(x + 2)
Factors are (3x - 2)(10x - 2) so x = 2/3 or 1/5 Check: 30 x 4/9 - 26 x 2/3 = 120/9 - 52/3 = -12/3 = -4 OK 30 x 1/25 - 26/5 =30/25 - 26/5 = 6/5 - 26/5 = 20/5 = -4 OK 60
26x.6 will give you the answer
38 = 26x - 7x 38 = 19x (38/19) = x 2 = x
3x2+26x+16 When factorised: (3x+2)(x+8)
Supose she has x of type 1. Then she has (26-x) of type 2. So x*(26-x) = 153 or x2 - 26x + 153 = 0 so (x-9)*(x-17) = 0 so the numbers are 9 and 17.