As a product of its prime factors: 3*3*3*3 = 81 and 4*3 = 12
2 x 3 x 3 x b x c = 18bc
3 x 5 x c x d = 15cd
2 x 2 x 2 x 3 x b x c
2 x 2 x 2 x 3 x B x C is the expression.
6,000 = 6 X 10^3 or 6e+3
The solution to this equation can not be determined
As a product of its prime factors: 3*3*3*3 = 81 and 4*3 = 12
6 x 10^9 or 6e+9
Int = 3x^(2) dy y = 3x^(3) / 3 + c y = x^(3) + C
18 9,2 3,3,2 2 x 3 x 3 x c x c x c =18c3
4e+0 x 6e+0 = 2.4e+1
0.0006 = 6e-4 or 6 x 10^-4
6e - 1272 = 0
sqrt(1) + 3*sqrt(x) = 1 + 3*x^1/2So the antiderivative is x + [3*x^(3/2)]/(3/2) + c = x + 2*x^(3/2) + c where c is the constant of integration.
3 x 7 x 37 = 777, a = 3 & c = 7
A Maclaurin series is centered about zero, while a Taylor series is centered about any point c. M(x) = [f(0)/0!] + [f'(0)/1!]x +[f''(0)/2!](x^2) + [f'''(0)/3!](x^3) + . . . for f(x). T(x) = [f(c)/0!] + [f'(c)/1!](x-c) +[f''(c)/2!]((x-c)^2) + [f'''(c)/3!]((x-c)^3) + . . . for f(x).