Q: What is the integral of 3 x square?

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square root x

(1/8)(x-sin 4x)

replace square root o x with t.

No. A square number is one that has an integral as its square root. For example, 9 is a square number because 3 x 3 = 9. There is no whole number that gives you 11 when multiplied by itself.

If you mean integral[(2x^2 +4x -3)(x+2)], then multiply them out to get: Integral[2x^3+8x^2+5x-6]. This is then easy to solve and is = 2/4x^4+8/3x^3+5/2x^2-6x +c

Related questions

The general form is (2/3)*x^(3/2) + C

the integral of the square-root of (x-1)2 = x2/2 - x + C

square root x

sqrt(x^3) (x^3)^.5 x^1.5 1.5+1=2.5 1/2.5=.4 Answer: .4x^2.5+c

(1/8)(x-sin 4x)

Integral of sqrt(2x) = integral of (2x)1/2 = √2/(3/2)*(x)3/2 + c = (2√2)/3*(x)3/2 + c where c is the constant of integration. Check: ( (2√2)/3*(2x)3/2 + c )' = (2√2)/3*(3/2)(x)(3/2)-1 + 0 = √2*(x)1/2 = √2x

replace square root o x with t.

No. A square number is one that has an integral as its square root. For example, 9 is a square number because 3 x 3 = 9. There is no whole number that gives you 11 when multiplied by itself.

The integral of -x2 is -1/3 x3 .

If you mean integral[(2x^2 +4x -3)(x+2)], then multiply them out to get: Integral[2x^3+8x^2+5x-6]. This is then easy to solve and is = 2/4x^4+8/3x^3+5/2x^2-6x +c

(ex)3=e3x, so int[(ex)3dx]=int[e3xdx]=e3x/3 the integral ex^3 involves a complex function useful only to integrations such as this known as the exponential integral, or En(x). The integral is:-(1/3)x*E2/3(-x3). To solve this integral, and for more information on the exponential integral, go to http://integrals.wolfram.com/index.jsp?expr=e^(x^3)&random=false

-cos(x) + constant