X^2 + 5 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: 0 plus or minus i times the square root of 5.
x = 0 + 2.23606797749979i
x = 0 - 2.23606797749979i
where i is the square root of negative one.
To factor the expression (5x^2 + 8x - 21), we look for two numbers that multiply to (5 \times -21 = -105) and add to (8). These numbers are (15) and (-7). We can then rewrite the expression as (5x^2 + 15x - 7x - 21) and factor by grouping: (5x(x + 3) - 7(x + 3)). Thus, the factored form is ((5x - 7)(x + 3)).
x^2 -5x-6 factors to: (x-6)(x+1)
5x
If that's -144, the answer is (5x + 12)(5x - 12)
Yes, if there is no remainder after division, the divisor is a factor.
50x2 - 18Factor out the common factor of 2:= 2 (25x2 - 9)Factor the difference of two squares:= 2 (5x + 3) (5x - 3)
2
5x^2(5x + 1)
If that was 2x^2 + 5x + 2, it would factor to (2x + 1)(x + 2)
5x(x - 2)
Answer: Part A: 5x^10−80x^2 Part B: 5x^2(x^4+4)(x^2+2)(x^2−2) Step-by-step explanation: Factor 5x^10−80x^2 5x^10−80x^2 This is how you would factor it =5x^2(x^4+4)(x^2+2)(x^2−2)
5x^2(x^2 + 5)
5x(6x + 9y + 2)
(5x + 3)(4x^2 + 1)
To factor the expression (5x + 10), first identify the greatest common factor of the terms, which is 5. You can then rewrite the expression as (5(x + 2)). Thus, the factored form of (5x + 10) is (5(x + 2)).
(5x - 2)(x - 5)
3x2 - 5x - 2 can be factored into (3x + 1) (x - 2)