14x2-7x2-16 7x2-16 (this can't be simplified any more)
If that's +14x + 3, the answer is (2x + 3)(4x + 1)
7(x + 3)(x - 3)
(x + 2)(x - 7)
We are looking for a factorization like 6x² + 7x - 5 = (_x + _)(_x - _) where we need to fill in the numbers in the blanks. Since the first and third blanks multiply to 6, they have to be 1 and 6 or 2 and 3. Similarly, the second and fourth blanks multiply to 5 so they must be 1 and 5. By trial and error, we arrive at the factorization 6x² + 7x - 5 = (2x - 1)(3x + 5).
7(x - 1)(x + 3)
14x squared minus 7x to the 3rd power can be factored to 7x2(2-x).
14x2-7x2-16 7x2-16 (this can't be simplified any more)
14x2 - 39x - 35 = (7x + 5)(2x - 7)
if its x(squared) its 7x(cubed) if its 2xX its 14x(squared)
(7x + 8)(7x - 9)
Pi Ok, it really cannot be answered without knowing to what it is equal and to which form of the equation you are referring: (7x)^2 - 14x = 49x^2 - 14x =7(7x^2 - 2x) or 7(x^2) - 14x = 7(x^2 - 2x)
14x
7x + 8
I suppose that would be 14x2 - 7x3. Just take out the common factor, 7x2. Divide each term by this factor to find the other factor.
(x + 1)(x - 8)
7x2 -4x -5x2 +2x = 2x2 -2x