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We are looking for a factorization like

6x² + 7x - 5 = (_x + _)(_x - _)

where we need to fill in the numbers in the blanks. Since the first and third blanks multiply to 6, they have to be 1 and 6 or 2 and 3. Similarly, the second and fourth blanks multiply to 5 so they must be 1 and 5. By trial and error, we arrive at the factorization

6x² + 7x - 5 = (2x - 1)(3x + 5).

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Wiki User

14y ago

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The factors of 6x^2 = 23x = 4 are (6x + 1)(x - 4)

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9y ago
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6x2-7x-3 = (3x+1)(2x-3)

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14y ago
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(x + 3)(5x - 2)

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12y ago
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The factors are: (3x - 1)(2x + 3).

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9y ago
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(4x - 3)(x - 1)

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7y ago
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Q: What are the factors of 6x squared plus 7x minus 3?
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