14x2-7x2-16 7x2-16 (this can't be simplified any more)
If that's +14x + 3, the answer is (2x + 3)(4x + 1)
7(x + 3)(x - 3)
(x + 2)(x - 7)
We are looking for a factorization like 6x² + 7x - 5 = (_x + _)(_x - _) where we need to fill in the numbers in the blanks. Since the first and third blanks multiply to 6, they have to be 1 and 6 or 2 and 3. Similarly, the second and fourth blanks multiply to 5 so they must be 1 and 5. By trial and error, we arrive at the factorization 6x² + 7x - 5 = (2x - 1)(3x + 5).
7(x - 1)(x + 3)
14x squared minus 7x to the 3rd power can be factored to 7x2(2-x).
14x2-7x2-16 7x2-16 (this can't be simplified any more)
14x2 - 39x - 35 = (7x + 5)(2x - 7)
if its x(squared) its 7x(cubed) if its 2xX its 14x(squared)
Pi Ok, it really cannot be answered without knowing to what it is equal and to which form of the equation you are referring: (7x)^2 - 14x = 49x^2 - 14x =7(7x^2 - 2x) or 7(x^2) - 14x = 7(x^2 - 2x)
(7x + 8)(7x - 9)
14x
7x + 8
I suppose that would be 14x2 - 7x3. Just take out the common factor, 7x2. Divide each term by this factor to find the other factor.
(x + 1)(x - 8)
If that's +14x + 3, the answer is (2x + 3)(4x + 1)