The greatest remainder when dividing by a number is always one less than that number. Therefore, for the divisors 3, 8, and 5, the greatest remainders would be 2 (for 3), 7 (for 8), and 4 (for 5). Among these, the largest remainder is 7, which corresponds to the divisor 8.
The Greatest Common Divisor (GCD) for 3 30 is 3.
The Greatest Common Divisor of 15, 18 3.
The Greatest Common Divisor of 57, 90 is 3.
The Greatest Common Divisor (GCD) for 21 39 is 3.
The greatest common divisor of 27 and 30 is 3.
The greatest remainder when dividing by 3 is 2. When you divide any integer by 3, the possible remainders are 0, 1, or 2. For example, if you divide 7 by 3, the quotient is 2 and the remainder is 1, while dividing 8 by 3 gives a remainder of 2, which is the highest possible remainder for that divisor.
It must be less else you have not divided properly; you could divide again 1 or more times!If the remainder is equal to the divisor (or equal to a multiple of the divisor) then you could divide again exactly without remainder. If the remainder is greater but not a multiple of the divisor you could divide again resulting in another remainder.E.g. Consider 9/2. This is 4 remainder 1. Let's say our answer was 3 remainder 3; as our remainder "3" is greater than the divisor "2" we can divide again so we have not carried out our original division correctly!
The greatest remainder when dividing by 5 is 4. This is because when a number is divided by 5, the possible remainders are 0, 1, 2, 3, and 4. Since 4 is the highest value in this set, it is the greatest remainder one can obtain when using 5 as the divisor.
The Greatest Common Divisor (GCD) for 12 3 is 3.
The Greatest Common Divisor (GCD) for 3 30 is 3.
The Greatest Common Divisor is 3
The Greatest Common Divisor of 15, 18 3.
Greatest Common Divisor (GCD) for 5 3 is 1.
Greatest common divisor of 12 and 15 is 3.
greatest common divisor of 60 and 231 is 3.
3
No because it will have a remainder of 2