The greatest remainder when dividing by a number is always one less than that number. Therefore, for the divisors 3, 8, and 5, the greatest remainders would be 2 (for 3), 7 (for 8), and 4 (for 5). Among these, the largest remainder is 7, which corresponds to the divisor 8.
The Greatest Common Divisor (GCD) for 3 30 is 3.
The Greatest Common Divisor of 15, 18 3.
The Greatest Common Divisor of 57, 90 is 3.
The Greatest Common Divisor (GCD) for 21 39 is 3.
The greatest common divisor of 27 and 30 is 3.
It must be less else you have not divided properly; you could divide again 1 or more times!If the remainder is equal to the divisor (or equal to a multiple of the divisor) then you could divide again exactly without remainder. If the remainder is greater but not a multiple of the divisor you could divide again resulting in another remainder.E.g. Consider 9/2. This is 4 remainder 1. Let's say our answer was 3 remainder 3; as our remainder "3" is greater than the divisor "2" we can divide again so we have not carried out our original division correctly!
The Greatest Common Divisor (GCD) for 12 3 is 3.
The Greatest Common Divisor (GCD) for 3 30 is 3.
The Greatest Common Divisor is 3
The Greatest Common Divisor of 15, 18 3.
Greatest Common Divisor (GCD) for 5 3 is 1.
Greatest common divisor of 12 and 15 is 3.
greatest common divisor of 60 and 231 is 3.
3
No because it will have a remainder of 2
The answer depends on what the divisor is.
an exact divisor of a number is one that leaves no remainder (a remainder of zero)--example: 27 divided by 3 is 9 but 27 divided bt 4 is 6 remainder 3 so 4 is not an exact divisor of 27 but 3 is