It must be less else you have not divided properly; you could divide again 1 or more times!
If the remainder is equal to the divisor (or equal to a multiple of the divisor) then you could divide again exactly without remainder. If the remainder is greater but not a multiple of the divisor you could divide again resulting in another remainder.
E.g. Consider 9/2. This is 4 remainder 1. Let's say our answer was 3 remainder 3; as our remainder "3" is greater than the divisor "2" we can divide again so we have not carried out our original division correctly!
Because if the remainder is greater, then you could "fit" another divisor value into it. if they are equal, then you can divide it easily. Thus, the remainder is always lower than the divisor.
The remainder is less than the divisor because if the remainder was greater than the divisor, you have the wrong quotient. In other words, you should increase your quotient until your remainder is less than your divisor!
The remainder can be greater than the divisor when the dividend is significantly larger than the divisor. In division, the remainder is the amount that is left over after dividing the dividend by the divisor. If the dividend is much larger than the divisor, it is likely that the remainder will also be larger than the divisor.
If the remainder were greater than the divisor, you'd be able to take another divisor out of it.
If the remainder is greater than the divisor then you can divide it once more and get one more whole number and then have less remainders.
It SHOULD always be less than the divisor... Otherwise your answer is wrong.
The problem would not end
No.
Your quotient that you arrived at is too small. Increase the answer for the quotient, so that the remainder is from zero to (divisor minus one)
Because if the remainder is greater, then you could "fit" another divisor value into it. if they are equal, then you can divide it easily. Thus, the remainder is always lower than the divisor.
less than
9. The divisor must be greater than the remainder. A 1 digit divisor that is greater than 8 can only be 9.