The greatest remainder when dividing by 3 is 2. When you divide any integer by 3, the possible remainders are 0, 1, or 2. For example, if you divide 7 by 3, the quotient is 2 and the remainder is 1, while dividing 8 by 3 gives a remainder of 2, which is the highest possible remainder for that divisor.
The Greatest Common Divisor is 3
Yes 3 will go into 51 an exact number (17) of times with no remainder. In other words 3*17=51
greatest common divisor of 60 and 231 is 3.
If the divisor of a division problem is 4, any number between 0 and 3 (inclusive) can be a remainder for that problem.
It means that there is no remainder in the problem. For example 9/3=3. The nine is the dividend, and the first three is the divisor. There was no remainder, so it divided evenly.
The greatest remainder when dividing by a number is always one less than that number. Therefore, for the divisors 3, 8, and 5, the greatest remainders would be 2 (for 3), 7 (for 8), and 4 (for 5). Among these, the largest remainder is 7, which corresponds to the divisor 8.
The Greatest Common Divisor (GCD) for 12 3 is 3.
The Greatest Common Divisor (GCD) for 3 30 is 3.
The Greatest Common Divisor is 3
Yes 3 will go into 51 an exact number (17) of times with no remainder. In other words 3*17=51
The Greatest Common Divisor of 15, 18 3.
Greatest Common Divisor (GCD) for 5 3 is 1.
greatest common divisor of 60 and 231 is 3.
Greatest common divisor of 12 and 15 is 3.
It must be less else you have not divided properly; you could divide again 1 or more times!If the remainder is equal to the divisor (or equal to a multiple of the divisor) then you could divide again exactly without remainder. If the remainder is greater but not a multiple of the divisor you could divide again resulting in another remainder.E.g. Consider 9/2. This is 4 remainder 1. Let's say our answer was 3 remainder 3; as our remainder "3" is greater than the divisor "2" we can divide again so we have not carried out our original division correctly!
3
The answer depends on what the divisor is.