+2, -6, -2, +6 and repeat.
The sequence appears to follow the pattern of ( n^3 - 1 ) for ( n = 1, 2, 3, 4, 5 ). Specifically, the numbers correspond to ( 1^3 - 1 = 0 ), ( 2^3 - 1 = 7 ), ( 3^3 - 1 = 26 ), and ( 4^3 - 1 = 63 ). Therefore, the next number would be ( 5^3 - 1 = 124 ). Thus, the next number in the sequence is 124.
3 and 1/7
The number is 1.
The pattern in the sequence 0, 7, 26, 63, 124 involves the formula ( n^3 - n ), where ( n ) is a positive integer starting from 1. Specifically, for each ( n ): ( 1^3 - 1 = 0 ) ( 2^3 - 2 = 7 ) ( 3^3 - 3 = 26 ) ( 4^3 - 4 = 63 ) ( 5^3 - 5 = 124 ) Thus, the next number in the sequence would be ( 6^3 - 6 = 210 ).
Only the number 1.
The pattern seems to be +1 +3 +1 +3 (3+1 = 4, 4+3 = 7, 7+1 = 8, etc...) So next in the sequence would be 12.
11
5 8 7 10 9 12 11 14 The pattern is +3, -1, +3, -1, +3, -1, +3
12
is this question number 10? 4n - 1 creates the pattern 3, 7, 11, 15, 19, etc.
7
It is 7
You double the number before it and add 1.
7 is the next number in the pattern
There is no number pattern in 781013. But there is a number pattern in the numbers 7, 8, 10, 13. 7+1=8 8+2=10 10+3=13 Can you see the pattern? And the next number in this sequence would be ... ?
Each successive number is the sum of the previous number times 2, plus 1.
It is 2, assuming the pattern is repeated as given. 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1... If the intended pattern is to continue to subtract 1 from the last number, then the 5479th digit of the pattern will be -5470.