prime squares
Since 11 is a prime number, its only divisors are 1 and itself.
Oh, isn't that a happy little question! The divisors of 543 are the numbers that can divide evenly into it without leaving a remainder. In this case, the divisors of 543 are 1, 3, 181, and 543. Just like in painting, each divisor plays a special role in creating a beautiful masterpiece of numbers.
You need at least two numbers to find a GCF.
squares of prime numbers
Squares of prime numbers are the only numbers with three factors, since there must be only one nontrivial divisor for a number to have three factors. That number must thus be prime.
A perfect number is only classified as a perfect number because all of its proper divisors add up to itself. For example, the proper divisors of six are one, two and three. Those numbers added together equal six. Therefore, six is a perfect number.
There is only 1 value of N that satisfies 2029 x N has exactly three divisors: N = 2029 To have exactly three divisors, the number must be the square of a prime number. 2029 is a prime number with exactly 2 divisors (1 and 2029). Thus the only number with exactly three divisors of which two are 1 and 2029 is 20292 (= 4116841), making N = 2029.
59 is a prime number. 1 and 59 are the only divisors of 59.
Prime numbers have two and only two divisors. The number 1 only has one.
yes. The only divisors of a prime number are itself and 1. Without counting the prime number, the sum of it's divisors is always 1.
A composite number is a positive integer greater than 1 that has more than two distinct positive divisors. In this case, the number 51 is a composite number because it has divisors other than 1 and itself, such as 3 and 17. Numbers 31, 41, and 61 are all prime numbers, as they only have two distinct positive divisors, 1 and the number itself.
16,81,12 well thats only i know
There are no numbers that fit your description.
An integer (call it 'x') has exactly 3 divisors if and only if it is the square of a prime number. In other words, to generate a list of integers with exactly 3 divisors, just keep squaring prime numbers. A number with 3 divisors cannot be prime (a prime number has only 2 divisors, 1 and itself). So it must be a composite number, which is a number that can be factored as a product of prime numbers (Fundamental Theorem of Arithmetic) -- i.e. a composite number must have at least one prime divisor. In the case where the number has only 3 divisors, two of them are 1 and the number itself (neither of which are prime). Therefore the third divisor must be a prime number. So the three divisors of 'x' are: 1, p, x where p is prime. Now since p is a divisor (or factor) of x, and the only other divisor besides 1 and x itself, x must equal p*p -- or x=p^2 . Obvious x can't equal p*x and if x = p*1, x=p so x is prime, or has only 2 divisors... If x = p^(3) , then x = p*p* p , or p*(p^2) ... this means that p^2 would also have to be a divisor of x, and this would contradict with x having only 3 divisors. For the same reason, x = p^(greater than 3) is also not possible. So the only possibility is that an integer with exactly 3 divisors is the square of a prime number "p". The divisors are 1, p, and p^2. I'm sure there's a simpler, more elegant way of explaining this, but it should be clear enough.
Only 2 goes into both 18 and 14. The prime divisors of 14 are 2 and 7. The prime divisors of 18 are 2, 3, and 3. The only common divisor is 2.
The prime numbers are numbers greater than 1 that have no divisors other than 1 and themselves. Out of the numbers 21, 23, 22, and 27, only 23 is a prime number because it is only divisible by 1 and 23 itself. The other numbers have divisors other than 1 and themselves, making them composite numbers.
The only numbers which divide into 89 exactly are 1 and 89. These are called factors or divisors. Any number which has exactly 2 divisors (1 and the number itself) is a prime number.