Not necessarily.
Unless graded on a curve, 60% is an F.
(b b b)( b b b )(b d g a)(b....)(c c c c)(c b b b)(a a a b)(a...d)(b b b)(b b b)(b d g a)(b....)(c c c c)(c b b b)(d d c a)(g.....)
a b c c c c b a g g a b g a b c c c c b a g b a a b c c c c b a g g a b a b c d b c e c b a b a g g
B b b b b b b d g a b c c c c c b b b a a b a d b b b b b b b d g a b c c c c c b b b d d c a g
It all depends on your school districts grading scale. It's a C at my kids' school!
Let the number be X, then B% = B/100 → B% of X = C → B/100 x X = C → X = C ÷ (B/100) = C x 100/B = 100C ÷ B So to find the number, divide C by B percent.
Assume that B is 100% A therefore is 140% —> B + 40% C therefore is 120% —> B + 20% Therefore A : C = 140 : 120 Therefore A exceeds C by 16.67%
Not necessarily.
On the traditional grading scale, 94% is an A. In fact, in most classes, 92 or lower is below an A 100% - 98% is an A+ 97% - 93% is an A 92% - 90% is an A- 89% - 88% is a B+ 87% - 83% is a B 82% - 80% is a B- 79% - 78% is a C+ 77% - 73% is a C 72% - 70% is a C- etc.
Letter Grade. 94 - 100. A.| 90 - 93. A-.| 87 - 89. B+.| 83 - 86. B.| 80 - 82. B-.| 77 - 79. C+.| 73 - 76. C.| 70 - 72. C-.| 67 - 69. D+. |63 - 66. D.| 60 - 62. D-.| < 60. F.|i hoped this helped
76% is a "C"
10 out of 12 gives you 83% which is a B.
78%is basicly a C+or B-
no B+ is a 77% - 79% 68% is a C+
a = variable b = 40%a a - b = c
B