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What does 2 c b t a c mean?
2 x b x t x a x c to the power 2
Can anyone give you the flute chords of moon river?
The Sequence is as follows: G D2 C2 / B A G F G / C B A G F G / C D / E C G E / D C G E / D C E G C2 B / A B A G A / C ... G D2 C2 / B A G F G / C B A G F G / C D / E C E G C2 D2 C2 G / B A G F G / C B A G F C / C E D E C / (Repeat 2x Then End). or The Sequence for the Higher Sound Ver. Of Moon River A E2 D2 / C#2 B A G A / D C#2 B A G A / D E / F# D A F# / E D A F# / E D F# A D2 C#2/ B C#2 B A B / D ... A E2 D2/ C#2 B A G A / D C#2 B A G A / D E / F# D F# A D2 E2 D2 A / C#2 B A G A / D C#2 B A G D / D F# E F# D / (Repeat 2x Then End).
What are the notes on the recorder for Jingle Bells?
(b b b)( b b b )(b d g a)(b....)(c c c c)(c b b b)(a a a b)(a...d)(b b b)(b b b)(b d g a)(b....)(c c c c)(c b b b)(d d c a)(g.....)
What are the piano notes for my heart will go on?
verse 1)C,C,C,C,B,C,C,B,C,D,E,D 2)C,C,C,C,B,C,C,G (Low) 3) C,C,C,C,B,C,C,B,C,D,E,D 4)C,C,C,C,B,C,C,G (Low) chorus 5)C,D,G (Low),G (High),F,E,D 6)E,F,E,D,C,B,C,B,A,B 7)C,D,G (Low),G (High),F,E,D 8)E,F,E,D,C,B,C,B,C,D *Reminder: 3 repeats as 1,4 repeats as 2, and 7 repeats as 5*
What are the piano notes for only hope?
hello person, the piano notes are: Example: .| A = a# C| a = a natural O| ----------------------------------- M| -Intro- -| T| 5|-b-b-b--a-G-G--f-e-|-C-D-e-D-C-c-C--| A| 4|-------------------|----------------| B| 3|-----a----e--------|-F-----G--------| N| 2|-------------------|----------------| A| B| -Verses- B| E| 5|----------------|----------------|----------------|----------------| R| 4|---------e---b--|---------e---b--|----e-b-----e-b-|----e-b-----F-G-| .| 3|-C---G----------|-----G----------|-a-------e------|-a--------G-----| C| 2|----------------|-b--------------|----------------|----------------|
What is proof of Heron's Formula?
This is a proof that uses the cosine rule and Pythagoras' theorem. As on any triangle with c being the opposite side of θ and a and b are the other sides: c^2=a^2+b^2-2abcosθ We can rearrange this for θ: θ=arccos[(a^2+b^2-c^2)/(2ab)] On a right-angle triangle cosθ=a/h. We can therefore construct a right-angle triangle with θ being one of the angles, the adjacent side being a^2+b^2-c^2 and the hypotenuse being 2ab. As the formula for the area of a triangle is also absinθ/2, when a and b being two sides and θ the angle between them, the opposite side of θ on the right-angle triangle we have constructed is 4A, with A being the area of the original triangle, as it is 2absinθ. Therefore, according to Pythagoras' theorem: (2ab)^2=(a^2+b^2-c^2)^2+(4A)^2 4a^2*b^2=(a^2+b^2-c^2)^2+16A^2 16A^2=4a^2*b^2-(a^2+b^2-c^2)^2 This is where it will start to get messy: 16A^2=4a^2*b^2-(a^2+b^2-c^2)(a^2+b^2-c^2) =4a^2*b^2-(a^4+a^2*b^2-a^2*c^2+a^2*b^2+b^4-b^2*c^2- a^2*c^2-b^2*c^2+c^4) =4a^2*b^2-(a^4+2a^2*b^2-2a^2*c^2+b^4-2b^2*c^2+c^4) =-a^4+2a^2*b^2+2a^2*c^2-b^4+2b^2*c^2-c^4 (Eq.1) We will now see: (a+b+c)(-a+b+c)(a-b+c)(a+b-c) =(-a^2+ab+ac-ab+b^2+bc-ac+bc+c^2)(a^2+ab-ac-ab-b^2+bc+ac+bc-c^2) =(-a^2+b^2+2bc+c^2)(a^2-b^2+2bc-c^2) =-a^4+a^2*b^2-2a^2*bc+a^2*c^2+a^2*b^2-b^4+2b^3*c-b^2*c^2+2a^2*bc-2b^3*c+(2bc)^2-2bc^3+a^2*c^2-b^2*c^2+2bc^3-c^4 =-a^4+2a^2*b^2+2a^2*c^2-b^4+(2bc)^2-c^4-2b^2*c^2 =-a^4+2a^2*b^2+2a^2*c^2-b^4+2b^2*c^2-c^4 (Eq.2) And now that we know that Eq.1=Eq.2, we can make Eq.1=(a+b+c)(-a+b+c)(a-b+c)(a+b-c) Therefore: 16A^2=(a+b+c)(-a+b+c)(a-b+c)(a+b-c) A^2=(a+b+c)(-a+b+c)(a-b+c)(a+b-c)/16 =[(a+b+c)/2][(-a+b+c)/2][(a-b+c)/2][(a+b-c)/2] And so if we let s=(a+b+c)/2 A^2=s(s-a)(s-b)(s-c)
What did the pythagorean theorm do for math?
If you know two sides of a right angle triangle, you can figure out the third by using the following formula: A*A+B*B=C*C or A**2+B**2=C**2 or C*C-B*B=A*A or C**2-B**2=A**2 or C*C-A*A=B*B or C**2-A**2=B**2 A is the bottom side if the right angle is at the bottom left, B is The only vertical(strait up and down) line if A is correct, and C is the last line.
Show that among all rectangles with area A the square has the minimum perimeter?
Suppose sqrt(A) = B ie the square with sides B has an area of A and its perimeter is 4*B. Now consider a rectangle with sides C and D whose area is A. So C*D = A = B*B so that D = B*B/C Perimeter of the rectangle = 2*(C+D) = 2*C + 2*D = 2*C +2*B*B/C Now consider (C-B)2 which, because it is a square, is always >= 0 ie C*C + B*B - 2*B*C >= 0 ie C*C + B*B >= 2*B*C Multiply both sides by 2/C (which is >0 so the inequality remains the same) 2*C + 2*B*B/C >= 4*B But, as shown above, the left hand side is perimeter of the rectangle, while the right hand side is the perimeter of the square.
Rearrange a equals 2b - c to make b the subject?
a = 2b - c a + c = 2b (a+c)/2 = b b = (a+c)/2
How do you complete a square in a math problem?
Here are the steps: ax^2 + bx + c = 0 Subtract c and divide by a x^2 + (b/a)x = -(c/a) Take the square of (b/a)/2 and add it to both sides (x + ((b/a)/2))^2 = -(c/a) + ((b/a)/2)^2 Take the square root of both sides Subtract ((b/a)/2) and you have your solutions: x = -(c/a) + ((b/a)/2)^2 - ((b/a)/2) x = (c/a) - ((b/a)/2)^2 - ((b/a)/2)
Evaluate a - b - c if a equals -15 b equals 5 and c equals -2?
If a = -15, b = 5 and c = -2 a - b - c = -15 - 5 - (-2) = -20 + 2 = -18
How do you find a leg in a right triangle?
In a right the triangle with legs a, b and hypotenuse c, a^2 = c^2 - b^2 or b^2 = c^2 - a^2.
What is the formula for a Venn Diagram?
A or B or C = A + B + C - A and B - A and C - B and C - 2 (A and B and C) I'm not sure by the way;
A minus b plus c whole square?
If you mean (a-b+c)^2, then... a^2 - ab + ac - ab + b^2 - bc + ac - bc + c^2 = a^2 + b^2 + c^2 - 2ab + 2ac - 2bc.
Asquare plus b square plus c square -ab -bc -ca equals 0 then show that a equals b equals c?
a^2 + b^2 + c^2 - ab - bc - ca = 0=> 2a^2 + 2b^2 + 2c^2 - 2ab - 2bc - 2ca = 0 => a^2 - 2ab + b^2 + b^2 - 2bc + c^2 + c^2 - 2ca + a^2 = 0 => (a - b)^2 + (b - c)^2 + (c - a)^2 = 0 Each term on the left hand side is a square and so it is non-negative. Since their sum is zero, each term must be zero. Therefore: a - b = 0 => a = b b - c = 0 => b = c.
What is (a-b plus c)2?
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
What is the surface area of a cuboid?
The answer should be: (2*a*b)+(2*b*c)+(2*c*a)
