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In this case, you probably typed something like, "If a>b, then a-c > b-c". This would be called the subtraction property of inequality, and is one of the rules used to solve inequalities.
B c bc bc bc bcbcbcbc
CA CAG A CAG A GAGG F* (THATS THE TOP BLACK F OR WATEVER IF IT HAS A * IT MEANS ON TOP) D B* DB*AB* DB*AB* CGG B*A BC BCDC DACB* B*B*AC B* B* B* A CB*AG EFGG F urs faithfully ...... ......
'Meet the Flintstones' was performed by the B-52s (calling themselves the BC-52s).
"B. C. Rich Warlock" is the name of electric guitars and bass guitars made by B. C. Rich. They have a distinct shape and are used by some popular musicians.
David C. B. Harvey has written: 'Real estate mortgages' -- subject(s): Forms (Law), Mortgages, Real property
If a < b, and c is positive, then ac < bcIf a < b, and c is negative, then ac > bc(inequality swaps over!)
A+BC+AC+B=A+BC+AC+B unless any of these variables has an assigned value.
There is no distributive property of addition over multiplication. The equation works if a + (b * c) = (a + b)*(a + c) = a2 + ab +ac +bc => a + bc = a2 + ab +ac +bc ie a = a2 + ab + ac = a*(a+b+c) and that, in turn requires that a = 0 or a+b+c = 1 If a, b and c are fractions than the second condition requires the fractions to sum to 1 - not be equal to 1.
The probability of ac and bc is 1/5.
associative? single replacement
a+bc --> ac+b
(a + b)/(a - b) = (c + d)/(c - d) cross multiply(a + b)(c - d) = (a - b)(c + d)ac - ad + bc - bd = ac + ad - bc - bd-ad + bc = -bc + ad-ad - ad = - bc - bc-2ad = -2bcad = bc that is the product of the means equals the product of the extremesa/b = b/c
transitive
Yes, for example (a + bi)(c + di) = ac + adi + bic + bidi, and commutative property works as well --> ac + adi + bci + bdi² --> ac + (ad + bc)i + bd(-1) = (ac - bd) + (ad + bc)i
A+bc---> b+ac
AC=5 AB=8 A=1 B=8 C=5 BC=40
Possibly distribution, as it seems that a c was distributed to the a and the b.