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Unfortunately this question cannot be answered unless we know what substance we are talking about. You can't mix this weight and volume measure unless we know the mass of the substance, clearly different substances have different masses and density. For example 25 tonnes of water has a volume of about 32 cubic yards, 25 tonnes of uranium has a volume of only 1.7 cubic yards because it is so dense. 25 tonnes of expanded polystyrene has a volume of 1326 cubic yards!
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How many cubic feet in 192 cubic yards?
There are 5,184 cubic feet in 192 cubic yards. This can be calculated by multiplying the number of cubic yards (192) by 27 (since there are 27 cubic feet in a cubic yard).
What is 25 feet by 13 feet by 4 inches deep into cubic yards?
To convert the dimensions to yards, we first convert inches to yards by dividing by 36 (since 1 yard = 36 inches). Then we multiply the dimensions to get the volume in cubic yards. 25 feet = 25 feet 13 feet = 13 feet 4 inches = 4/36 yards = 1/9 yards Volume = 25 * 13 * 1/9 = 36.111 cubic yards (rounded to 3 decimal places).
How do you convert square yards to tonnage?
To convert square yards to tonnage, you need to know the material's density in pounds per cubic yard. Then, you can multiply the area in square yards by the thickness in yards to get the volume in cubic yards. Finally, multiply the volume by the material's density to get the tonnage.
How many tons of 2b limestone is needed for a trench 2ft by 2ft by 100 ft long?
To calculate the volume of limestone needed for the trench, first convert the dimensions to feet (2ft = 0.67 yd, 100ft = 33.33 yd). Then calculate the volume (0.67yd x 0.67yd x 33.33yd = 14.8 cubic yards). Finally, limestone weighs approximately 2,700 lbs per cubic yard, so you would need around 40 tons of 2b limestone.
How many cubic yards of dirt would it take to fill an area 30 feet wide by 30 feet long by 4 inches deep?
It would take 3.7 cubic yards of dirt to fill an area that is 30 feet wide, 30 feet long, and 4 inches deep. This can be calculated by converting the dimensions to yards (10 yards x 10 yards x 0.33 yards) and then multiplying them together.
