Wiki User
∙ 13y ago1. Find volume of spheres = 4/3pr3 and multiply by 4 since there are 4 spheres.
2. Find volume of units cell = l 3 = (2Ö2r)3.
3. Find volume of empty space = vol unit cell minus volume of spheres.
4. Divide volume empty space by volume of unit cell.
It works out to 25.952
Wiki User
∙ 13y agoIn cubic closest packing, also known as face-centered cubic (fcc) structure, the fraction of empty space is approximately 26%. This means that about 26% of the total volume is empty space between closely packed spheres.
4 significant figures.
There are 3 significant figures in 94.2.
101330 has 6 significant figures.
4487 has four significant figures.
4 significant figures.
Count the significant figures in each number. Calculate the minimum of these numbers. Do the multiplication Round the product to the LEAST number of significant figures, determined above.
4 significant figures.
Because density expressed in two significant figures depends on your accuracy of your measurements of mass and volume to calculate as well as any variables that you are expected to use.
There are 4 significant figures in 0.0032. Seems to be only 2 significant figures in this number.
There are 3 significant figures in 94.2.
145.75+2.3*10^-1 145.75+0.23 145.98 As 2.3*10^-1 has two significant figures, our answer must have two significant figures 145.98 150 As the 5.98 rounds up to the nearest significant figure 1.5*10^2
0.0359
There are four significant figures in 700.0. The zeros after the decimal point are significant since they indicate precision.
There are four significant figures in 0.1111.
20.2 has three significant figures.
There are four significant figures in 0.005120.
0.0375 has three significant figures.