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Is it possible to have a perimeter of 46 and an area of 42 as a rectangle?
No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
What is the dimensions of a rectangle with a perimeter of 34 inches and an area of 42 inches squared?
The dimensions of the rectangle are 3 inches by 14 inches
The perimeter of a rectangle is 26 units. What is the greatest possible area of the rectangle in square units?
42 square units.
Is it possible for a rectangle to have an area of 42 and a perimeter of 46?
Make it 2 wide and 21 long and you've got it.
What is the perimeter of a rhombus with an area of 42 and an altitude of 6?
28
Can the perimeter be 18 and still the area is 42?
For a given perimeter, the greatest possible area is enclosed by a circle.A circle with a circumference of 18 has a diameter of (18/pi) and a radius of (9/pi).Its area is (pi R2) = (pi 92/pi2) = 81/pi = 25.78 (rounded)So an area of 42 cannot be enclosed by a perimeter of 18.
What is the largest and smallest perimeter possible for a rectangle with a area of 42?
Largest = 86, Smallest 26
Is it possible to have a perimeter of 46 and an area of 42 as a rectangle?
No, it is not possible for a rectangle to have a perimeter of 46 and an area of 42 simultaneously. For a rectangle, the perimeter ( P ) is given by ( P = 2(l + w) ), and the area ( A ) is ( A = l \times w ), where ( l ) is the length and ( w ) is the width. Solving these equations shows that the dimensions needed for these values are inconsistent, meaning no such rectangle exists.
What is the dimensions of a rectangle with a perimeter of 34 inches and an area of 42 inches squared?
The dimensions of the rectangle are 3 inches by 14 inches
Is it possible for a rectangle to have an area of 42 and a perimeter of 46?
Make it 2 wide and 21 long and you've got it.
The perimeter of a rectangle is 26 units. What is the greatest possible area of the rectangle in square units?
42 square units.
How do you find the area and perimeter of 42 centimeters wide and 14 centimeters?
Assuming that it's a rectangle then:- Area = 42*14 = 588 square cm Perimeter = 42+42+14+14 = 112 cm
What is the area and the perimeter 7cm by 6cm?
Area 42 cm2, perimeter 26 cm.
What is the perimeter of a rhombus with an area of 42 and an altitude of 6?
28
What is the area of a regular hexagon if the perimeter is 42 inches?
The area is about 127.3 square inches.
The area of a rectangle is 42 square feet.If the length and width are whole numbers what are the least and greatest possible perimeters?
To find the least and greatest possible perimeters of a rectangle with an area of 42 square feet, we need to identify the pairs of whole numbers (length and width) that multiply to 42. The pairs are (1, 42), (2, 21), (3, 14), (6, 7). The perimeter is calculated as ( P = 2(\text{length} + \text{width}) ). The least perimeter is from the pair (6, 7), giving ( P = 26 ), while the greatest perimeter is from the pair (1, 42), giving ( P = 86 ).
What is the area if the perimeter of the square is 168 inches?
Perimeter = 168 inches so 4*length of side = 168 inches Length of side = 168/4 = 42 inches So area = 42*42 = 1764 square inches.
