If the velocity is uniform, then the final velocity and the initial velocity are the same. Perhaps you meant to say uniform acceleration. In any event, the question needs to be stated more precisely.
zero because the initial and final velocity is constant . so,difference bet. final velocity and initial velocity is zero
The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.
You can only know the distance for sure if acceleration or deceleration is constant. Add the start and end velocities and divide by two and then multiply by the time to get your distance.
You can use the equation: Displacement = (final velocity squared - initial velocity squared) / (2 * acceleration). Plug in the values of final velocity, initial velocity, and acceleration to calculate the displacement.
To find acceleration, you take Vi [Initial Velocity] and you subtract if from Vf [Final Velocity.] (Vi - Vf) If they Vi and Vf are already given, you take the two givens and you subtract them from each other. Vi minus Vf. Do not do Vf minus Vi or it will be wrong. After you do that, you divide your answer from T [Time] (Vi - Vf) a= _____ t Once you get your answer, that will be your acceleration.
zero because the initial and final velocity is constant . so,difference bet. final velocity and initial velocity is zero
The equation that relates the distance traveled by a constantly accelerating object to its initial velocity, final velocity, and time is the equation of motion: [ \text{distance} = \frac{1}{2} \times (\text{initial velocity} + \text{final velocity}) \times \text{time} ] This equation assumes constant acceleration.
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
v = 2s/t - u where u=initial velocity, v=final velocity, s = distance and t = time
This equation represents the final velocity squared when an object is accelerating from an initial velocity over a certain distance. It is derived from the kinematic equation (v^2 = u^2 + 2as), where (v) is the final velocity, (u) is the initial velocity, (a) is the acceleration, and (s) is the distance traveled.
Its final velocity, the distance covered.
assuming uniform decelaration, . number of g's = ((v^2 - u^2) / (2 * s)) / 9.82 v = final velocity u = initial velocity s = distance
You use the information you're given, along with the equations and formulas you know that express some kind of relationship between the information you're given and the initial and final velocity.
To find the distance traveled, we can use the formula: distance = initial velocity * time + 0.5 * acceleration * time^2. The initial velocity is 75 miles per second, the final velocity is 145 miles per second, and the time is 15 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time. Plug in the values to find the acceleration and then calculate the distance traveled in 15 seconds.
The formula for non-uniform motion is given by: [ v_f = v_i + at ] where ( v_f ) is the final velocity, ( v_i ) is the initial velocity, ( a ) is the acceleration, and ( t ) is the time taken.
Average speed = 1/2 (initial speed + final speed) Time = (distance)/(average speed)
You can only know the distance for sure if acceleration or deceleration is constant. Add the start and end velocities and divide by two and then multiply by the time to get your distance.