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Assuming you mean its range is 10m, then use the equation:

v0 = sqrt(r*g/sin(2θ)), where r is its range, θ is its initial angle, and g is acceleration from gravity.

=sqrt(10m*9.8m/s2/sin(90))

=sqrt(98.0m2/s2)

=9.9m/s

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13y ago
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3w ago

To find the initial velocity given an angle of 45 degrees and a distance of 10 meters, you can use the projectile motion equation for horizontal distance: x = V₀ * cos(θ) * t, where x is the horizontal distance, V₀ is the initial velocity, θ is the angle, and t is the time of flight. Since you know the angle and distance, you can solve for the initial velocity given those values.

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Q: How do you find initial velocity given only 45 degrees and a distance of 10 meters?
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