Wiki User
∙ 13y agoAssuming you mean its range is 10m, then use the equation:
v0 = sqrt(r*g/sin(2θ)), where r is its range, θ is its initial angle, and g is acceleration from gravity.
=sqrt(10m*9.8m/s2/sin(90))
=sqrt(98.0m2/s2)
=9.9m/s
Wiki User
∙ 13y agoTo find the initial velocity given an angle of 45 degrees and a distance of 10 meters, you can use the projectile motion equation for horizontal distance: x = V₀ * cos(θ) * t, where x is the horizontal distance, V₀ is the initial velocity, θ is the angle, and t is the time of flight. Since you know the angle and distance, you can solve for the initial velocity given those values.
Velocity is the rate of change of distance over time. This relationship is described by the equation velocity = distance/time, where velocity is measured in units like meters per second, distance is measured in units like meters, and time is measured in units like seconds. As velocity increases, the distance covered in a given amount of time also increases.
Meters per second
The final velocity can be calculated using the formula: final velocity = initial velocity + (acceleration * time). If the initial velocity is 0 m/s, then the final velocity would be 10 m/s^2 * 7s = 70 m/s.
Velocity is the rate of change of an object's position with respect to time. The formula for calculating velocity is velocity = distance/time, where velocity is typically measured in meters per second (m/s).
You cannot. You need to know either the initial speed or angle of projection (A).
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
To find the initial velocity of the box when it fell out, you can use the formula: final velocity squared = initial velocity squared + 2 * acceleration * distance. Given that the final velocity is 0 m/s, acceleration is 3 m/s^2, and distance is 24 meters, you can solve for the initial velocity.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
anything shot up with that initial velocity. There isn't anything in specific.
To find the horizontal distance traveled by the soccer ball, you can use the equation: horizontal distance = horizontal velocity x time. The horizontal velocity is given by the formula Vx = V0 cosθ, where V0 is the initial velocity and θ is the angle of projection. Substituting the given values: Vx = 10.0 m/s * cos(30°) = 8.66 m/s. Then, the horizontal distance = 8.66 m/s * 3.2 s = 27.71 meters.
When you say initial speed I assume there will be accelleration. If so you could you: s = ut + 1/2at^2. or s = 1/2(u + v)t where s is distance in meters u is initial velocity in ms v is the final velocity in ms a is accelleration in ms^-2 t is time in s If there is no accelleration then s = ut
The initial velocity can be found using the kinematic equation: (d = v_0t + \frac{1}{2}at^2), where (d = 32m), (a = -9.81 m/s^2) (acceleration due to gravity), and (t) can be calculated using the time it takes for the rock to fall from a height of 450m. The initial velocity (v_0) is the horizontal component of velocity; therefore, it is the found by (v_0 = \frac{d}{t}).
The distance traveled can be calculated using the equation: distance = initial velocity * time + 0.5 * acceleration * time^2. If the acceleration is 0.5 m/s^2 and time is 20 seconds, we would need to know the initial velocity to determine the total distance traveled.
The average deceleration of the person underwater can be estimated by calculating the change in velocity over the distance traveled. First, calculate the initial velocity when the person enters the water using the equation v^2 = u^2 + 2as, where v = final velocity (0 m/s), u = initial velocity, a = acceleration due to gravity (-9.8 m/s^2), and s = distance traveled (2 m). After finding the initial velocity, divide it by the time taken to stop underwater (you can assume a typical value based on personal experience or research) to estimate the average deceleration.
Velocity equal distance divided by time. For example, an object that traveled 5 metes in 10 seconds had a velocity of 5/10 meters per second which is .5 meters per second. Velocity is speed in a direction. Sometimes a navigate or positive number is sufficient as the direction. Other times you will need to be more specific, such as .5 meters per second East or 1.3 meters per second 30 degrees East of North.
Velocity is the rate of change of distance over time. This relationship is described by the equation velocity = distance/time, where velocity is measured in units like meters per second, distance is measured in units like meters, and time is measured in units like seconds. As velocity increases, the distance covered in a given amount of time also increases.
To find the distance traveled before stopping, we can use the equation of motion: distance = initial velocity * time + 0.5 * acceleration * time^2. Since the final velocity is 0 m/s, the distance traveled is 13m/s * 5s = 65 meters.