Assuming you mean its range is 10m, then use the equation:
v0 = sqrt(r*g/sin(2θ)), where r is its range, θ is its initial angle, and g is acceleration from gravity.
=sqrt(10m*9.8m/s2/sin(90))
=sqrt(98.0m2/s2)
=9.9m/s
Velocity is the rate of change of distance over time. This relationship is described by the equation velocity = distance/time, where velocity is measured in units like meters per second, distance is measured in units like meters, and time is measured in units like seconds. As velocity increases, the distance covered in a given amount of time also increases.
Meters per second
It will depend upon the initial velocity of the body. If 'u' be the initial velocity of the body, then the final velocity will be: v = u + at (v = final velocity, a = acceleration, t = time) i.e., v=u+10*7 = (u + 70) m/sec. If u=0 (i.e the initial velocity be zero) then final velocity, v=70 m/sec.
Velocity is the rate of change of an object's position with respect to time. The formula for calculating velocity is velocity = distance/time, where velocity is typically measured in meters per second (m/s).
You cannot. You need to know either the initial speed or angle of projection (A).
If the initial velocity is 50 meters per second and the launch angle is 15 degrees what is the maximum height? Explain.
To find the initial velocity of the box when it fell out, you can use the formula: final velocity squared = initial velocity squared + 2 * acceleration * distance. Given that the final velocity is 0 m/s, acceleration is 3 m/s^2, and distance is 24 meters, you can solve for the initial velocity.
Acceleration of the arrow is -3m/s2A = (velocity minus initial velocity) / time
anything shot up with that initial velocity. There isn't anything in specific.
When you say initial speed I assume there will be accelleration. If so you could you: s = ut + 1/2at^2. or s = 1/2(u + v)t where s is distance in meters u is initial velocity in ms v is the final velocity in ms a is accelleration in ms^-2 t is time in s If there is no accelleration then s = ut
The initial velocity can be found using the kinematic equation: (d = v_0t + \frac{1}{2}at^2), where (d = 32m), (a = -9.81 m/s^2) (acceleration due to gravity), and (t) can be calculated using the time it takes for the rock to fall from a height of 450m. The initial velocity (v_0) is the horizontal component of velocity; therefore, it is the found by (v_0 = \frac{d}{t}).
The distance traveled can be calculated using the equation: distance = initial velocity * time + 0.5 * acceleration * time^2. If the acceleration is 0.5 m/s^2 and time is 20 seconds, we would need to know the initial velocity to determine the total distance traveled.
To find the horizontal distance traveled by the soccer ball, you can use the equation: horizontal distance = horizontal velocity x time. The horizontal velocity is given by the formula Vx = V0 cosθ, where V0 is the initial velocity and θ is the angle of projection. Substituting the given values: Vx = 10.0 m/s * cos(30°) = 8.66 m/s. Then, the horizontal distance = 8.66 m/s * 3.2 s = 27.71 meters.
so what you need to do is find the velocity that the person enters the water and then use the equation v sub final squared = v sub initial squared + 2*acceleration(final distance-initial distance). final velocity is zero, find the initial velocity yourself and use 2 as the final distance where the initial distance is 0, solve for acceleration. Easy way: the decelleration would have been twice that provided by gravity because the diver decellerated to zero in half the distance of the dive. The diver starts at zero and hits max velocity in 4 meters then goes from max velocity to zero in 2 meters. 2 x 9.81 m/s2 = ___
Velocity equal distance divided by time. For example, an object that traveled 5 metes in 10 seconds had a velocity of 5/10 meters per second which is .5 meters per second. Velocity is speed in a direction. Sometimes a navigate or positive number is sufficient as the direction. Other times you will need to be more specific, such as .5 meters per second East or 1.3 meters per second 30 degrees East of North.
Velocity is the rate of change of distance over time. This relationship is described by the equation velocity = distance/time, where velocity is measured in units like meters per second, distance is measured in units like meters, and time is measured in units like seconds. As velocity increases, the distance covered in a given amount of time also increases.
Initial velocity can be measured in the same units as any other velocity. In SI, that would be meters per second, but often km / hour are used, or (in a minority of countries) feet/second or miles/hour.