For a single phase 3 HP motor at 208 volts the amperage is 18.7 amps. For a three phase 3 HP motor at 208 volts the amperage is 10.5 amps. This figure is derived at by taking the full load amps at 230 volts and adding 10%. As the voltage goes down the amperage goes up. For 200 volt motors 15% is added to the FLA of a 230 volt motor.
To calculate watts, you need to multiply the voltage (in volts) by the current (in amps). For the 208 volts, 8 amps heating element: Watts = 208 volts * 8 amps = 1664 watts For the 110 volts, 8 amps heating element: Watts = 110 volts * 8 amps = 880 watts
The watts is the volts times the amps So 208 x 50 watts, or 10.4 kW.
If you have 208 between legs, you have 120 from each leg to neutral (208 divided by 1.73). Assuming a balanced load, this would be 1 KW per leg - 1000 divided by 120 = 8.33 amps per leg. Your question contradicts itself. If you have 208v, the answer above is correct, 8.33 amps. If you have 480v, you have 3.6 amps.
To calculate the amperage load, use the formula: Amperage = Power (in watts) / (Voltage (in volts) * Power Factor). For a 45 kVA load at 208-120 volts, assuming a power factor of 1, the amperage would be approximately 173A.
One Megawatt = 1,000,000 watts. Watts = Volts x Amps or voltage x current. Hence if you know the voltage then Amps = 1,000,000 watts / Volts.
To calculate watts, you need to multiply the voltage (in volts) by the current (in amps). For the 208 volts, 8 amps heating element: Watts = 208 volts * 8 amps = 1664 watts For the 110 volts, 8 amps heating element: Watts = 110 volts * 8 amps = 880 watts
#8 copper
The watts is the volts times the amps So 208 x 50 watts, or 10.4 kW.
If you have 208 between legs, you have 120 from each leg to neutral (208 divided by 1.73). Assuming a balanced load, this would be 1 KW per leg - 1000 divided by 120 = 8.33 amps per leg. Your question contradicts itself. If you have 208v, the answer above is correct, 8.33 amps. If you have 480v, you have 3.6 amps.
To calculate the amperage load, use the formula: Amperage = Power (in watts) / (Voltage (in volts) * Power Factor). For a 45 kVA load at 208-120 volts, assuming a power factor of 1, the amperage would be approximately 173A.
One Megawatt = 1,000,000 watts. Watts = Volts x Amps or voltage x current. Hence if you know the voltage then Amps = 1,000,000 watts / Volts.
1,040 watts or 1.04 KW.
The formula you are looking for is I = W/E. Amps = Watts/Volts.
To calculate the amperage, you can use the formula: Amps = (kW × 1000) / (√3 × Volts). Plugging in the values, we get: Amps = (45 × 1000) / (√3 × 208) ≈ 131.1 amps. So, the hot water heater would draw approximately 131.1 amps.
To calculate the current draw, use the formula: Current (A) = Power (W) / (Voltage (V) * √3). Plugging in the values, we get Current = 30000W / (208V * √3) ≈ 78.7A. So, a 30KW strip heater operating at 208 volts 3-phase would draw approximately 78.7 amps.
I bought a 208 cc snowblower , how many horsepower is that ?
You cannot convert 2.6 kw to amps with that information only. In order to convert watts to amps, you also need to know either current or voltage. This is because watts is volts times amps, and volts is current times resistance