Wiki User
∙ 11y ago1 cal/gdegC x 225g x (100 - 50.5)degC heat to the boiling point
540 cal/g x 225g heat to vaporize the water
0.5 cal/gdegC x 225 g x (133-100)degC heat to chang temp of steam
= 11137.5 cal + 121500 cal + 3712.5 cal = 14850 cal
Wiki User
∙ 11y ago1600
Pure water turns into steam at 100 degrees Celsius (212 degrees Fahrenheit) at standard atmospheric pressure.
Steam. The reason for this is water boils at the temperature of 212 degrees F. Steam can be heated to much higher temperatures than that. Some engines that are water cooled has steam at temperatures of over 700 degrees. Water basically becomes a plasma at this temperature.
The answer is 675 calories.
It takes 6 SI calories to raise one liter of water by 6 degrees Celsius.
This is the latent heat of vaporisation of water, which at standard pressure, is 539 calories (per gram).
To vaporize 1 gram of boiling water at 100 degrees Celsius, it would require approximately 2260 joules, which is equivalent to about 0.54 calories. This energy is needed to break the intermolecular bonds holding water molecules together, allowing them to escape into the gas phase.
To convert 4 kg of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to calculate the heat required to raise the temperature of ice to 0 degrees Celsius, melt the ice to water at 0 degrees Celsius, raise the temperature of water to 100 degrees Celsius, and then convert water to steam at 100 degrees Celsius. The total amount of heat needed can be calculated using the specific heat capacities and latent heats of fusion and vaporization of water.
To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.
To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.
1600
540 cal
The steam point of the Celsius scale is 100 degrees Celsius. At this temperature, water boils and turns into steam.
Water changes into steam or water vapor above 100 degrees Celsius.
The steam point of water is when water boils and turns into vapor at a temperature of 100 degrees Celsius (212 degrees Fahrenheit) at standard atmospheric pressure. At this point, water transitions into steam as a gas.
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
Water becomes steam at 100 degrees Celsius under normal atmospheric pressure.