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Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4.

S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2.

The oxidizing agent is H2SO4 since it causes Cu to be oxidized.

The reducing agent is Cu since it causes S in H2SO4 to be reduced.

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What is the limiting reactant when 41.4 grams of cuo are exposed to 2.56 grams of h2 according to the equation cuo h2 yields cu h2o?

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The reaction CuO plus CO yields Co2 plus Cu is an example of oxidation or reduction or both or neither?

The reaction CuO + CO → CO2 + Cu is an example of reduction because copper(II) oxide (CuO) gains electrons to form copper (Cu). Reduction is the gain of electrons by a species.


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CuO + 2HCl --> CuCl2 + H2O This equation is a double displacement; because Cu (Copper) has pushed out O (oxygen), so that Cu can be with Cl (chlorine). Also, H (Hydrogen) has pushed out Cl to be with O. Both elements have pushed out their partner, therefore a double displacement.


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CuO, Ag2O, and MgO cannot be reduced by hydrogen because they are already in their elemental form (copper, silver, and magnesium, respectively) and are stable. Fe2O3 (iron oxide) and PbO (lead oxide) can be reduced to their respective metals by hydrogen through a chemical reaction where hydrogen acts as a reducing agent.


Reaction between copper oxide and hydrogen?

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What are the products of a chemical reaction between CuO plus CO2?

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What is reduction of a metal oxide?

Reduction of a metal oxide refers to the process of removing oxygen from the metal oxide compound, typically by adding a reducing agent such as carbon or hydrogen. This leads to the formation of the pure metal and a by-product such as carbon dioxide or water. Reduction reactions are commonly used in metallurgy to extract metals from their ores.