2Na + 2H2O -------> 2NaOH + H2
Since the given reaction is already balanced, simply divide 12 by the coefficient of Na in the equation, resulting in a quotient of 6. Multiply the coefficients of the original equation by 6 to obtain the answer: 6 X 2 = 12 moles of water required. (Note that the equation should have been written with mostly capital letters as follows: 2 Na + 2 H2O -> 2 NaOH + H2.)
The word equation for the reaction of Li, Na, and K with H2O is: Lithium (Li) + Water (H2O) → Lithium hydroxide (LiOH) + Hydrogen gas (H2) Sodium (Na) + Water (H2O) → Sodium hydroxide (NaOH) + Hydrogen gas (H2) Potassium (K) + Water (H2O) → Potassium hydroxide (KOH) + Hydrogen gas (H2)
The balanced equation for Na + HNO3 is: 2Na + 2HNO3 -> 2NaNO3 + H2
The reaction is:2 Na + 2 H2O = 2 NaOH + H2
2Na + 2H2O -------> 2NaOH + H2
2Na + 2H2O -> H2 + 2NaOH
The balanced chemical equation for the reaction between Na and H2O to form NaOH and H2 is: 2Na + 2H2O → 2NaOH + H2. The equation is balanced as the same number of atoms of each element are present on both sides of the equation.
Yes, the water and sodium produce sodium hydroxide and hydrogen!
Na + H2O --> NaOH + H2
No, the chemical equation provided is not balanced. It should be written as: 2Na + 2H2O → 2NaOH + H2.
NaOH + H2O ---> Na+(aq) + OH-(aq) + H2O or in Net Ionic terms NaOH ----> Na+(aq) + OH-(aq) There is no reaction. NaOH only ionizes.
The equation for the reaction of hydrogen gas (H2) and oxygen gas (O2) to form water (H2O) is: 2H2 + O2 -> 2H2O. This reaction is commonly known as the combustion of hydrogen.
Since the given reaction is already balanced, simply divide 12 by the coefficient of Na in the equation, resulting in a quotient of 6. Multiply the coefficients of the original equation by 6 to obtain the answer: 6 X 2 = 12 moles of water required. (Note that the equation should have been written with mostly capital letters as follows: 2 Na + 2 H2O -> 2 NaOH + H2.)
The skeleton equation for this reaction is: 2Na + 2H2O → 2NaOH + H2. This equation represents the reaction between sodium (Na) and water (H2O) to form sodium hydroxide (NaOH) and hydrogen gas (H2).
Na+ and Cl- are spectator ions.
The word equation for the reaction of Li, Na, and K with H2O is: Lithium (Li) + Water (H2O) → Lithium hydroxide (LiOH) + Hydrogen gas (H2) Sodium (Na) + Water (H2O) → Sodium hydroxide (NaOH) + Hydrogen gas (H2) Potassium (K) + Water (H2O) → Potassium hydroxide (KOH) + Hydrogen gas (H2)