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What is acceleration on 8 kg mass if two forces F1 and F2 act on the object where F1 equals 20 N and F2 equals 15 N if F1 lies on a 0 deg angle and F2 lies 60 deg rotated upward from F1?
If we take F1 to be in the direction of a unit vector "i" and the direction perpendicular to the direction of F1 to have a unit vector "j" , F (net) = ((15*cos(60))+20) i + (15*sin(60)) j = 27.5 i + 12.99 j N Mass * Acceleration = F (net) => Acceleration = F (net) / mass Acceleration = (3.4375 i + 1.62375 j ) m/sec2
When you think of the trait of the parent plants why is this result surprising?
what trait or traits did the plant in the f generation to the offspring in the F2 gen. what did the difference in the F1 and F2 offspring show Mandel
What was the second generation of offspring in Mendel's expierment called?
The parental generation is called the P generation. The offspring, or filial generation, is called F, with the first generation designated F1, the second F2,etc.
Contrast the offspring in the f 1 generation to the offspring in the f 2 generation?
In a typical Mendelian cross, the F1 generation consists of offspring that are heterozygous for a particular trait, displaying the dominant phenotype. In contrast, the F2 generation arises from the self-fertilization or interbreeding of F1 individuals, resulting in a phenotypic ratio that often includes both dominant and recessive traits, typically in a 3:1 ratio. This generation showcases greater genetic variation, as it includes homozygous dominant, heterozygous, and homozygous recessive individuals. Thus, while F1 offspring are uniform in phenotype, the F2 generation reveals the underlying genetic diversity and segregation of alleles.
What are f2 offsprings?
They are result of a cross among F 1 .
C programing of regula falsi method?
try this out...#include#includefloat valcal(float);int main(){float a,b,f,x,f1,f2,f3,i;a=2;b=3;int flag=0;f1=valcal(a);f2=valcal(b);printf("\n\n%f %f",f1,f2);for(i=0;i
C programming of bisection method with output?
try this out...#include#includefloat valcal(float);int main(){float a,b,f,x,f1,f2,f3,i;a=2;b=3;int flag=0;f1=valcal(a);f2=valcal(b);//printf("\n\n%f %f",f1,f2);for(i=0;i
5f plus 1510f find the value of the variable is it f1 f2 f3 or f4 which one?
If you mean: 5f+10 = 10f then the value of f works out as 2
Simplify ff plus f plus fff plus f?
Denoting ff as f2 etc, f2 + f + f3 + f = f3 + f2 + 2f
What is the function of the f lock key on the computer keyboard?
The F Lock on a keyboard disables the use of function keys. E.G: F1 F2 F3 etc.
How can you pass the last maze in Dream Chronicles 2 The Eternal Maze?
INSTRUCTIONS: *do not follow the map because it is quite wrong *F-Forward R- right L lef-t If you use this step by step guide you must follow it exactly. If you miss a step it will not work and you will have to restart the level. R is for a right turn, L is for a left turn and F is for a step forward, LL is left twice which will make you turn around. Enter the maze, then F3 - L. You will see a broken barrel, ignore it. F4 - L - F2 - R - F4. Click on the key and ignore the head for now. LL - F4 - L - F2 - L - F2 - R - F2 - L - F3 - L - F1. Click on the key. LL - F1 - R - F1 - L - F2 - L - F1. Click on the key. Ignore the door for now. You now have 3 keys. We will now go to the chests and use the 3 keys. LL - F1 - R - F2 - L - F2 - L - F2 - R - F3 - R - F2 - R - F1. Use the key with one prong to open the chest, then click on the open chest and a gem will go into your inventory. LL - F1 - L - F2 - R - F2 - R - F2. Use the key with three prongs to open the chest, then click on the open chest and a gem will go into your inventory. LL - F2 - R - F4 - R - F2 - R - F2. Use the key with two prongs to open the chest, then click on the open chest and a gem will go into your inventory. Now we will go and put the gems in the heads. LL - F2 - L - F2 - L - F9 - L - F4 - L - F2 - R - F2 - R - F5. Put the green gem in the area just below the face and the head will glow blue. LL - F1 - R - F1. Use the red gem here. LL - F2. Use the blue gem here. A key will go into your inventory. Now we will go to the door and use this key. LL - F1 - L - F4 - L - F2 - L - F2 - R - F2 - L - F2 - R - F2 - L - F1. Use the cylinder key to open the door. F2 - L - F3. Click on the green potion and it will go into your inventory. Now we will go back to the entrance of the tunnel and exit the maze. LL - F3 - R - F3 - R - F2 - L - F2 - R - F2 - L - F6. You will now make the last turn. R - F4 and you will be out of the maze.
How do you make a division problem in c programming go into a decimal?
When dividing one integer with another, there's a high probability that the answer will not be an integer. To deal with this, you must cast the numerator or denominator to a floating point type (float or double). By way of an example, consider the following code snippet: int x=5, y=2; int z = x/y; float f1 = x/y; float f2 = ( float ) x/y; float f3 = x/( float ) y; printf( "x=%d, y=%d, z=%d, f1=%f, f2=%f, f3=%f\n", x, y, z, f1, f2, f3 ); Output: x=5, y=2, z=2, f1=2.000000, f2=2.500000, f3=2.500000 Clearly the correct answer is shown by f2 and f3. This is because we explicitly cast the numerator or denominator in each case. So long as we cast one or the other (or both), the result will be correct. If we don't cast either, then we're effectively only converting the result of the integer division, which is effectively the same as casting z to a float, as shown by f1. See the related links section for in-depth information on floating point arithmetic in C/C++.
How many different ways can you write a fraction that has numerator of 2 as a sum of fractions?
Infinitely many ways. Suppose you have found a way of writing the given fraction, F, as a sum of two fractions, f1 and f2.Take any other fraction g such that g < f1 and g is not equal to the absolute value of f1 - f2. Then consider (f1 - g) and (f2 + g). Since f1, f2 and g are all fractions, then so are (f1 - g) and (f2 + g). And their sum is F.
What will be the overall noise figure of two cascaded amplifiers?
say, overall noise figure =f noise figure of stage1=f1 noise figure of stage2=f2 f=f1+(f2-1)/g1 f1,f2 are in linear scale(not in dB) g1=gain in stage1
How can we prove that the sum of two arbitrary functions is a function further more if ab belong to Z how can we prove that aF1 plus bF2 is a function?
I'm not sure I really understand the question. If you have two functions, F1 and F2, then by definition of function you have: If X=Y then F(x)=F(y) for both F1 and F2 (F1+F2)(x) is defined as F1(X) + F2(X), and for every X there exists a unique F1(x) and F(2)(x) and the sum of these two numbers is obviously unique. If the question meant that the range of F1 and F2 were included in Z and how do you show that the range of F1 + F2 is also a subset of Z, then it's as simple as: the sum of two integers is an integer. and for the second part: the product of two integers is an integer.
What is special keys at the top of the keyboard also called F Keys?
They are function keys (F1, F2, F3, up to F12). F5 is the reload or refresh key, F11 is the full screen mode, and the other keys either have a use or none at all.
What is the difference between F2 and F?
F represents the generation of offspring resulting from the cross of two F1 individuals, while F2 represents the generation of offspring resulting from breeding two F1 individuals together. F2 generation shows more genetic variation compared to the F generation.
