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A graph that shows displacement plotted against time for a particle moving in a straight line. Let x(t) be the displacement of the particle at time t. The distance-time graph is the graph y=x(t), where the t-axis is horizontal and the y-axis is vertical with the positive direction upwards. The gradient at any point is equal to the velocity of the particle at that time. (Here a common convention has been followed, in which the unit vector i in the positive direction along the line has been suppressed. The displacement of the particle is in fact a vector quantity equal to x(t)i, and the velocity of the particle is a vector quantity equal to x(t)i.)
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RossA distance-time graph illustrates the relationship between distance traveled and time taken. It shows how the distance changes over time, with distance usually plotted on the y-axis and time on the x-axis. The slope of the graph represents the speed of the object being tracked.
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When do two different distance-time graphs have matching velocity-time graphs?
Two different distance-time graphs have matching velocity-time graphs when the slope of the distance-time graph represents the velocity in the velocity-time graph, as velocity is the derivative of distance with respect to time. This means that the steeper the distance-time graph, the greater the velocity on the velocity-time graph at that point.
What does the slope of a time vs distance graph equal?
The slope of a time vs distance graph represents the speed or velocity of an object. It is calculated as the change in distance divided by the change in time. A steeper slope indicates a greater speed.
In a distance-time graph the slope of is the ratio of time to distance?
The slope of a distance-time graph represents the speed of an object. It is calculated as the ratio of the change in distance to the change in time. A steeper slope indicates a faster speed.
Can a position time graph be created from a velocity time graph?
Yes, a position-time graph can be created from a velocity-time graph by integrating the velocity values over time. By finding the area under the velocity-time curve, you can determine how the position of an object changes over time.
How do you figure out the starting point of a distance vs time graph when given the velocity vs time graph and a function?
To find the starting point of a distance vs time graph from a velocity vs time graph and a function, you would integrate the velocity function to find the displacement function. The starting point of the distance vs time graph corresponds to the initial displacement obtained from the displaced function.
