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Acceleration = (change in speed) divided by (time for the change) = (0 - 36)/3 = -12 m/s2

The acceleration of gravity is 9.8 m/s2, so the passengers are pulled forward

against their seat belts with a 'force' of 1.22 Gs during the screech.

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13y ago
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2w ago

The acceleration of the car can be calculated using the formula: acceleration = (final velocity - initial velocity) / time. Substituting the values, we get acceleration = (0 m/s - 36 m/s) / 3 s = -36 m/s^2. Therefore, the acceleration of the car while stopping is -36 m/s^2.

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Q: What is the acceleration of a car that screeches to a stop if it takes 3 seconds to go from 36 meters per seconds to 0 meters per seconds?
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