25%
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
there is a 50% chance that the offspring will be tall.
To determine the probability of different offspring from the cross of genotypes BB, Bb, and bb, we first need to clarify the specific cross being made. If we are crossing BB (homozygous dominant) with Bb (heterozygous), the potential offspring would be 50% BB and 50% Bb. If we then cross this with bb (homozygous recessive), the resulting offspring would be 50% Bb and 50% bb. Thus, the probabilities for the offspring would be 50% Bb and 50% bb.
0 (there is no chance it will be short since tall is dominant over short). Hope this helps! - Biology Student
The offspring has a 50% chance of the dominate trait (while being heteroygous) and a 50% chance of having the recessive trait ( homozygous recessive).
The probability is 50%. There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
There are 3 probabilities: dominant homozygous, recessive homozygous, or heterozygous.
Impossible. You can only be heterozygous or homozygous, not both.
In a cross between a homozygous recessive parent (AA) and a heterozygous parent (Aa), the possible genotypes of the offspring are 50% homozygous recessive (AA) and 50% heterozygous (Aa). Therefore, the probability that an offspring will be homozygous recessive is 50%.
A cross between two individuals that are homozygous for different alleles will only produce heterozygous offspring. This is because each parent can only donate one type of allele, resulting in all offspring being heterozygous for that particular gene.
The probability that the offspring of a homozygous dominant parent (AA) and a heterozygous parent (Aa) will show a recessive phenotype is 0%. Since the homozygous dominant parent contributes only dominant alleles (A), all offspring will inherit at least one dominant allele (A) from the homozygous parent, resulting in either a homozygous dominant (AA) or a heterozygous (Aa) genotype, both of which express the dominant phenotype.
The probability of a homozygous recessive offspring depends on the genotypes of the parents. If we consider a simple Mendelian trait with two alleles (dominant "A" and recessive "a"), a homozygous recessive offspring (aa) will occur if both parents contribute a recessive allele. For instance, if both parents are heterozygous (Aa), the probability of producing a homozygous recessive offspring is 25%, as determined by a Punnett square. If one parent is homozygous dominant (AA) and the other is homozygous recessive (aa), the probability of a homozygous recessive offspring is 0%.
The probability that an individual heterozygous for a cleft chin and an individual homozygous for a chin without a cleft will produce offspring that are homozygous recessive for a chin without a cleft is fifty percent. You can calculate this by making a Punnet square.
To calculate the probability of a homozygous dominant (BB) offspring from a cross between two rabbits, we need to consider their genotypes. If both parents are heterozygous (Bb), the possible offspring genotypes would be BB, Bb, Bb, and bb, giving a probability of 1 out of 4, or 25%, for a homozygous dominant (BB) offspring. If one parent is homozygous dominant (BB) and the other is heterozygous (Bb), the probability of BB offspring is 1 out of 2, or 50%.
In a dihybrid cross between two heterozygous parents (AaBb x AaBb), the probability of producing homozygous recessive offspring for both traits (aabb) is 1/16. This is derived from the Punnett square, where the combinations of alleles reveal that out of 16 possible offspring, only one combination results in homozygous recessive for both traits. Thus, the fraction of homozygous recessive offspring is 1/16.
There are two forms of Homozygous inheritance: Homozygous Dominant, and Homozygous Recessive. In order for two parents that are Homozygous to produce a Heterozygous offspring, one of them MUST be Homozygous Dominant, and the other MUST be Homozygous Recessive.
If one parent is homozygous dominant (AA) and the other parent is homozygous recessive (aa), all offspring will inherit one dominant allele and display the dominant phenotype. Therefore, the probability of their offspring exhibiting the dominant phenotype is 100%.