The probability is 50%.
There are four probabilities: dominant homozygous, recessive homozygous, or heterozygous.
25%
Each parent contributes 50% of the genetic make-up of the offspring.
50%
75%. Explanation: if both parents are carriers than their Gametes would be Dd x Dd, resulting in DD (1/4), Dd (2/4), and dd(1/4), meaning that there is a 25% chance that they will have a child that has the disorder. DD = A normal child that lacks the recessive gene, therefore not a carrier Dd = A normal child that carries the recessive gene dd = A child with the disorder + carries the gene, hence the child's future offspring will carry it as well. Source: Self/Basic Punnet Square
I am unsure of the answer to this question, but I feel the need to remove the previous ridiculous answer stating that "women with down syndrome are sterile." They ARE indeed fertile. I am in search of the same information, and will be editing this post once I find the correct answer.
25%
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
because the recessive allele is still present in heterozygous individuals. these individuals have one dominant allele and so show the dominant phenotype but they are capable of producing offspring with the recessive condition
you have a 50/50 chance of producing both a male and female offspring, it really depends on whether or not your offspring's DNA will have XY chromosomes (male) or XX chromosomes (female)
No, AA and SS cannot give birth to AA offspring. In this scenario, there would be a 50% chance of producing AS offspring (heterozygous) and a 50% chance of producing SS offspring (homozygous recessive).
1/16
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
Each parent contributes 50% of the genetic make-up of the offspring.
Here are the four possibilities: AA Aa Aa aa Therefore there is a 25% chance of producing a homozygous dominant offspring (AA).
you have a 50/50 chance of producing both a male and female offspring, it really depends on whether or not your offspring's DNA will have XY chromosomes (male) or XX chromosomes (female)
Champagne is a dominant dilution gene. The ideal way to insure that any foal produced is champagne would be that one parent is homozygous for Champagne. This would result in 100% champagne foals from all matings.The second best way would be for both parents to be heterozygous champagne which would have a probability of producing 75% champagne foals.The third best way is if one parent is heterozygous for champagne which would have a 50% probability of producing a champagne foal.
producing or capable of producing offspring