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What is the probability of 2 heterozygous individuals producing a homozygous recessive offspring?
25%
What is the probability of each of the following sets of parents producing the give genotypes in their offspring?
Each parent contributes 50% of the genetic make-up of the offspring.
What is the probability of a down syndrome carrier male and a non-carrier female producing non-carrier children?
50%
What is the probability of producing a normal child by two parents who are carriers for an autosomal recessive disorder?
75%. Explanation: if both parents are carriers than their Gametes would be Dd x Dd, resulting in DD (1/4), Dd (2/4), and dd(1/4), meaning that there is a 25% chance that they will have a child that has the disorder. DD = A normal child that lacks the recessive gene, therefore not a carrier Dd = A normal child that carries the recessive gene dd = A child with the disorder + carries the gene, hence the child's future offspring will carry it as well. Source: Self/Basic Punnet Square
What is the probability of a Down syndrome woman and a non-carrier male producing non-carrier children?
I am unsure of the answer to this question, but I feel the need to remove the previous ridiculous answer stating that "women with down syndrome are sterile." They ARE indeed fertile. I am in search of the same information, and will be editing this post once I find the correct answer.
What is the probability of 2 heterozygous individuals producing a homozygous recessive offspring?
25%
What is the probability that two heterozygous parents would have an offspring that produced round seeds from Mendel?
When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
What was the probability that two heterozygous parents would have an offspring that produced round seeds?
If both parents are heterozygous for seed shape (Rr), their offspring would have a 75% chance of producing round seeds (3 out of 4 possible combinations), assuming round seeds (R) are dominant over wrinkled seeds (r).
From the cross AA x AA the probability of producing a homozygous dominant offspring is?
From the cross Aa x Aa, the probability of producing a homozygous dominant offspring is 1/4 or (0.25).
What is the probability that an offspring mouse will be born with the genotype ff ee?
To determine the probability of an offspring mouse being born with the genotype ff ee, you need to know the genotypes of the parent mice. If both parents are heterozygous (Ff Ee), the probability of producing ff offspring is 1/4 and for ee offspring is also 1/4. To find the probability of the combined genotype ff ee, you multiply these probabilities: (1/4) x (1/4) = 1/16. Thus, there is a 1/16 probability that an offspring mouse will have the genotype ff ee, assuming both parents are Ff Ee.
How can albinism in plants keep occurring if they cannot reproduce?
because the recessive allele is still present in heterozygous individuals. these individuals have one dominant allele and so show the dominant phenotype but they are capable of producing offspring with the recessive condition
What is the probability of producing a male offspring?
you have a 50/50 chance of producing both a male and female offspring, it really depends on whether or not your offspring's DNA will have XY chromosomes (male) or XX chromosomes (female)
Can AA and SS give birth to AA?
No, AA and SS cannot give birth to AA offspring. In this scenario, there would be a 50% chance of producing AS offspring (heterozygous) and a 50% chance of producing SS offspring (homozygous recessive).
What is the probability of producing a homozygous dominant offspring from the cross of AA and AA?
1/16
What is the probability that the offspring will be i barred females?
To determine the probability of offspring being i barred females, we need information about the genetic makeup of the parents, specifically their genotypes related to the i barred trait. If both parents carry the i barred allele, we can use a Punnett square to analyze the potential combinations. The resulting probability will depend on the specific alleles present in the parents. Generally, if both parents are heterozygous for the i barred trait, the probability of producing i barred females could be calculated based on the ratios established in the Punnett square.
What is the probability that two heterozygous parents would have an offspring that produced round seeds?
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
What is the probability of each of the following sets of parents producing the give genotypes in their offspring?
Each parent contributes 50% of the genetic make-up of the offspring.
