For that current you would need five 0000 (4/0) wires in parallel for each side of the circuit, and they would heat to 90 degrees C if used for any length of time according to the NEC tables. Those wires have a diameter of 0.46 inch exactly.
There are better ways of transmitting 153 kW if there is a higher voltage available.
To determine the wire size needed for 120VDC and 1275 Amps, you would use the formula: Wire size (AWG) = (Ampacity of wire)/(Current carrying capacity of wire). In this case, with 1275 Amps and 120VDC, the calculated wire size required is approximately 300 MCM (thousands of circular mils) which corresponds to a wire gauge of 250.
A #10 copper conductor with an insulation factor of 90 degrees C is rated at 30 amps.
Add 25% so it comes to 42 amps
For carrying 100 amps underground, typically a 2-gauge copper wire or a 1/0-gauge aluminum wire would be suitable. It's important to consult with a licensed electrician to ensure the correct wire size based on distance, voltage drop, and local electrical codes.
The recommended cable size for 210 amps would be at least 2/0 AWG (00 AWG) for optimal performance and safety. Make sure to consult the National Electrical Code (NEC) or a professional electrician to determine the exact cable size needed based on the installation requirements and conditions.
A wire size of at least 250 MCM (thousands of circular mils) is typically recommended for a current of 312 amps. Using wire size calculators or consulting with an electrician is advisable for specific installations to ensure the correct wire gauge is used for safety and efficiency.
#8 copper
A #10 copper conductor with an insulation factor of 90 degrees C is rated at 30 amps.
A parallel run of 750 MCM AWG conductors will handle 1000 amps. if we want 1000amps to flow, 250sqmm cable is enough.
To answer this question the pump voltage is needed.
Depending on size of Fridge. But AVERAGE is 12 volts for fridge, circuit necessity 15 amps 15 amps X 120 Volts=1800 watts minimum...I'm LEARNING myself
The formula you are looking for is Watts = Amps x Volts. Amps = Watts/Volts. This comes to 4 amps load. Minimum size fuse would be 5 amps.
Add 25% so it comes to 42 amps
As a service entrance wire you need AWG # 3/0 gauge copper.
Fuse SizesThe Amperage ratings [sizing] of fuses [and circuit breakers] is determined by the SIZE of the conductors [wires] in the circuit which they serve.The size of the wires is determined by the maximum expected current [measured in Amperes (Amps) or Milliamps (mA] needed by the electrical devices "fed" by the circuit.Therefore, the answer to your question is that there are many different "size" fuses which range in Amperage from thousandths of an Amp to hundreds of Amps.
For carrying 100 amps underground, typically a 2-gauge copper wire or a 1/0-gauge aluminum wire would be suitable. It's important to consult with a licensed electrician to ensure the correct wire size based on distance, voltage drop, and local electrical codes.
Almost any average size home today will requre a 200 amp service panel.
For service sizes of 100 amps and less a #8 bare copper conductor is required.