Actual voltage would be 240V. 4 AWG copper is capable of carrying 50A. At 200 ft, with a 50A load, voltage drop would be about 6V, which is within the acceptable 3% voltage drop for a branch circuit.
This is a voltage drop question. To answer the question about distance a voltage must be stated. That said a #10 copper conductor with an insulation factor of 75 or 90 degrees C are both rated at 30 amps.
A #16 copper conductor is not a wiring size that is used in homes. This is because the smallest breaker for residential use is rated for 15 amps. A #16 copper conductor is only rated at 13 amps. For a load of 13 amps over 100 feet a #12 copper would be required.
80 feet of 14 AWG wire has a resistance of about .2 ohms. So at 15 amps the voltage drop across the length of wire is about 3 volts. With 120 volt service, this should be fine. If you up the wire size to 12 AWG, the voltage drop would be 1.9 volts.
The number of automotive amps a 30-foot strand of copper wire can carry depends on the gauge (thickness) of the wire. For example, a 30-foot strand of 10-gauge copper wire can typically carry up to 40-50 amps for automotive use, while a 30-foot strand of 12-gauge wire might be limited to around 25-30 amps. It's important to consult wire ampacity tables and consider factors like temperature and voltage drop to ensure safe and effective performance.
The voltage has nothing to do with the capacity of a wire to handle current. A #12 copper wire with an insulation factor of 60, 75 or 90 degrees C is rated at 20 amps.
To answer this question a voltage must be given.
Depends upon the voltage. The formula for amperage or (wire size) is Watts / Voltage. If the voltage is 220 volts, then the amperage would be over 400 amps. This would require a large wire size to run it. If it were 440 volts, the amperage would be 1/2 or 200 amps. That would require a smaller wire size. As the voltage goes up, the amperage goes down. At a thousand volts, the amperage would only be 90 amps. A wire gauge or size of a #2 would carry 90 amps for small distances.
Wire is sized by the amperage that it will carry. 5 kW is 5000 watts. The equation to find watts is W = Amps x Volts. The equation to find amps is Amps = Watts/Volts. As you can see a voltage is needed to calculate the amperage. Once the amperage is stated, the wire size can be given for that particular amperage.
14
A # 14 copper conductor will be fine to carry 8 amps at 120 volts. This size conductor is rated at 15 amps.
The distance that a 6 gauge wire can carry 50 amps depends on factors like voltage drop and wire insulation. In general, a 6 gauge wire can carry 50 amps for up to 60-70 feet without significant voltage drop. However, it is recommended to consult with a professional electrician for accurate calculations and safety considerations.
This is a voltage drop question. To answer the question about distance a voltage must be stated. That said a #10 copper conductor with an insulation factor of 75 or 90 degrees C are both rated at 30 amps.
To answer this question a voltage and amperage must be stated. W = Amps x Volts.
The V stands for volts and A is amps. If for example you have a 12kVA device and are running off a voltage of 120 volts then Amps = 12000/120 = 100. You then use the calculated amps in a wire size table to get the correct size.
A #16 copper conductor is not a wiring size that is used in homes. This is because the smallest breaker for residential use is rated for 15 amps. A #16 copper conductor is only rated at 13 amps. For a load of 13 amps over 100 feet a #12 copper would be required.
AWG # 6 copper
Couple of things wrong here. 30 isn't a wire size. If you mean a wire that can carry 30 amps that would be # 10. Now it depends on how many # 10 wires you want to put into a conduit that governs the size of the conduit.