nitrogen aton in NH3 has one lone pair of electron
No, methane (CH4) does not have any lone pair electrons around the central carbon atom. Each hydrogen atom shares one electron with carbon in a single covalent bond.
CH4 has no lone pairs.It has 4 repulsive units.So shape is tetrahedral
In methane (CH4), the covalently bonded electrons are localized between the carbon atom and each hydrogen atom. In ammonia (NH3), the same is true for the nitrogen atom and each hydrogen atom. However, in ammonia, there is also a lone pair of electrons on the nitrogen atom that are not involved in covalent bonding.
covalent bonds --- sharing electrons
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No, methane (CH4) does not have any lone pair electrons around the central carbon atom. Each hydrogen atom shares one electron with carbon in a single covalent bond.
In methane (CH4), the central carbon atom does not have any lone pairs of electrons. Instead, it forms four single covalent bonds with the four hydrogen atoms around it.
Methane (CH4) does not have any lone pairs of electrons on the central carbon atom. All electrons are involved in bonding with the four hydrogen atoms, resulting in a tetrahedral geometry.
in water there are two bond pairs and two lone pairs where as in CH4 there are are four bond pairs nad no lone pair. in ch4 there is only bond pair to bond pair repulsion but in water there are three types of repulsions, lone to lone (greatest repulsion), lone to bond ( lesser repulsion ) and bond to bond ( the least repulsion) , therefore due to the presence of two lone pairs in water the bond pairs are repelled with greater force and they get compressed, reducing the ideal bond angle from 109.5 to 104.5 on the other hand, ch4 has only bond pairs and they dont repel each other that strongly so its angle is greater n its 109.5..
Option E (CH4) would not make a good electron pair donor in the formation of a coordinate covalent bond because methane does not possess a lone pair of electrons on the central carbon atom to donate for bond formation. The other options, A (H2O), B (NH3), C (PF3), and D (Cl-), are all capable of acting as electron pair donors due to the presence of lone pairs that can be shared with electron-deficient species.
CH4 has no lone pairs.So it is tetrahedral.
The pair of molecules with the strongest dipole-dipole interactions would be NH3-NH3 because ammonia (NH3) is a polar molecule with a significant dipole moment, leading to stronger attractions compared to the other options listed.
In CH4 molecule, the Carbon atom initially has four valence electrons, which are all used to form covalent bonds with the four Hydrogen atom. Hydrogen atom has only one valence electron, which is also used to form bonds with Carbon. Overally, there is no valence lone pair of electron in a molecule of CH4
CH4 (methane) is a neutral molecule and is neither a Lewis acid nor a Lewis base. Lewis acids are electron pair acceptors, while Lewis bases are electron pair donors. Since CH4 does not have any available lone pairs to donate or accept, it does not exhibit Lewis acid or base behavior.
CH4 has no lone pairs.It has 4 repulsive units.So shape is tetrahedral
In the redox reaction between methane (CH4) and 2 molecules of oxygen (O2) to form carbon dioxide (CO2) and 2 molecules of water (H2O), a total of 8 electrons are transferred.
It has no lone pairs.So it is tetrahedral