in water there are two bond pairs and two lone pairs where as in CH4 there are are four bond pairs nad no lone pair.
in ch4 there is only bond pair to bond pair repulsion but in water there are three types of repulsions, lone to lone (greatest repulsion), lone to bond ( lesser repulsion ) and bond to bond ( the least repulsion) , therefore due to the presence of two lone pairs in water the bond pairs are repelled with greater force and they get compressed, reducing the ideal bond angle from 109.5 to 104.5
on the other hand, ch4 has only bond pairs and they dont repel each other that strongly so its angle is greater n its 109.5..
The bond angle in water (H₂O) is less than that in methane (CH₄) primarily due to the presence of lone pairs of electrons in water. Water has a bent molecular shape with a bond angle of approximately 104.5 degrees, influenced by two lone pairs on the oxygen atom that repel the hydrogen atoms more strongly. In contrast, methane has a tetrahedral shape with a bond angle of about 109.5 degrees, where there are no lone pairs, allowing for a more symmetrical distribution of electron density around the central carbon atom.
Ozone (O₃) has a bond angle of approximately 117 degrees, which is larger than water's bond angle of about 104.5 degrees. This difference is primarily due to the presence of resonance structures in ozone, which allows for a more spread-out electron distribution and reduces the repulsion between bonding pairs. In contrast, water has two lone pairs that exert greater repulsive forces on the bonding pairs, resulting in a smaller bond angle. Additionally, the molecular geometry of ozone is bent, but it experiences less steric hindrance compared to water.
No, the bond angle for linear structure is 180 degrees.
ClO3 has the smaller bond angle than ClO4
Yes, water is a bend molecule with a bond angle of about 105 degrees. They are described as bent planar (or V shaped)
The water molecule's bond angle is about 104.45 degrees.
The approximate H-O-H bond angle in water is 104.5 degrees.
The lone pair - OH bond repulsion in water is greater than the OH bond- OH bond repulsion. In methane all of the bonds are the same so it has perfect tetrahedral symmetry. This is VSEPR theory
The approximate HOH bond angle in ice is around 109.5 degrees due to the tetrahedral arrangement of water molecules in the solid state. The hydrogen bonds in ice help hold the water molecules together in a regular pattern, contributing to the observed bond angle.
The bond angle in CO2 is 180 degrees.
The bond angle of AlCl3 is 120 degrees.
The bond angle of N2O is 180 degrees.
The bond angle for H2S is approximately 92 degrees.
Ozone (O₃) has a bond angle of approximately 117 degrees, which is larger than water's bond angle of about 104.5 degrees. This difference is primarily due to the presence of resonance structures in ozone, which allows for a more spread-out electron distribution and reduces the repulsion between bonding pairs. In contrast, water has two lone pairs that exert greater repulsive forces on the bonding pairs, resulting in a smaller bond angle. Additionally, the molecular geometry of ozone is bent, but it experiences less steric hindrance compared to water.
The bond angle in NI3 is approximately 107 degrees.
The bond angle for IO2 is around 120 degrees.
The bond angle for NBr3 is approximately 107 degrees.