2x - 4x + 3 = 0
-2x + 3 = 0
2x = 3
x = 3/2 = 1.5
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2x-3=4x+9 -2x-12=0 2x=-12 x=-6
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
Given, 4x2 - 4x + 3 = 0; then, 4x2 - 4x + 1 = (2x - 1)2 = -2, 2x - 1 = √-2 = ±i√2, and 2x = 1 ± i√2; therefore, x = ½(1 ± i√2).
If: y = x^2 -2x +4 and y = 2x^2 -4x +4 Then: 2x^2 -4x +4 = x^2 -2x +4 Transposing terms: x^2 -2x = 0 Factorizing: (x-2)(x+0) => x = 2 or x = 0 Therefore by substitution points of intersect are at: (2, 4) and (0, 4)
If -2x +14 = 0, -2x = -14, or x = 7.