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What are the solutions to the equation X2 plus 2x plus 2 equals 0?
x2 + 2x + 2 = 0 Use the quadratic formula: x = (-2 +- sqrt(4 - 8))/2 x = (-2 +- 2i)/2 = -1 +- i
What use the discriminant to determine the nature of the roots of x2 plus 2x plus 5 equals 0?
No real roots
Put the equation in the form ax2 plus bx plus c equals 0 x2-3 equals 3x2 plus 8x?
2x^2 + 8x + 3 = 0
What is the derivative of square root 2x-x2?
0
What are the solutions to the simultaneous equation of 2x plus y equals 5 and x squared -y squared equals 3 showing work?
2x + y = 5 . . . thus y = 5 - 2x x2 - y2= 3 . . . . now substitute for y in this equation. x2 - (5 - 2x)2 = 3 . . . and after expansion this becomes, x2 - 25 + 20x - 4x2 = 3 -3x2 + 20x - 28 = 0 . . . and this factors as, (-3x + 14)(x - 2) = 0 Then, x = 2 , x = 14/3 When x = 2, then 2x + y = 5 gives the result y = 1. When x = 14/3 then 2x + y = 5 gives the result y = -13/3.
Solve x2 plus 2x - 13 equals 2?
x2 + 2x - 13 = 2 x2 + 2x - 15 = 0 (x + 5)(x - 3) = 0 x + 5 = 0 and x - 3 = 0 so x = -5 and x = 3
What is the quadric equation for x2-2x-13 equals 0?
x = 4.74 or -2.74
2x equals x2 plus 4x-3?
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
What is the solution to x2 plus 10x plus 1 equals -12 plus 2x?
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
X2 - 2x - 5 equals 0?
x2 - 2x - 5 = 0 x2 - 2x + 1 = 6 (x - 1)2 = 6 x - 1 = ± √6 x = 1 ± √6
How do you solve x2-2x-3 equals 0?
x2-2x-3 = 0 (x+1)(x-3) = 0 x = -1 or x = 3
X squared plus 2x - 3 equals 0?
If: x2+2x-3 = 0 Then: x = 1 or x = -3
How do you solve the following quadratic equations with the India method A. x2-2x-13 equals 0 B. 4x2-4x plus 3 equals 0 C. x2 plus 12x-64 equals 0 D. 2x2-3x-5 equals 0?
Simply by using the formula x= -b +/- Underroot of (b2 - 4.a.c) / 2.a 2+x-6=2x+4
What are solutions for x2 plus 10x plus 1 equals -12 plus 2x?
x2+10x+1 = -12+2x x2+8x+13 = 0 The solution: x = -4 + the square root of 3 or x = -4 - the square root of 3
How do you factor x squared minus 2x minus 10 minus 5 equals 0?
x2-2x-10-5 = 0 x2-2x-15 = 0 (x+3)(x-5) = 0 x = -3 or x = 5
Y equals x2 plus 2x plus 1?
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
