This quadratic equation can be solved by three methods: (a) factoring (b) completing the square (c) using the quadratic equation formula.Factoring:25x2+20x+4 = 0(5+2)(5x+2) = 0Solution: x = -2/5 also x = -2/5 (they both have equal roots)
A=0 b=0 c=0
0
2x^2 + 8x + 3 = 0
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
Factorises as (5x-2)(5x-2) so x = 0.4 25x2= 4, -20x = -8 4 - 8 + 4 = 0
It is: (5x-1)(5x+1) = 0 when factored
This quadratic equation can be solved by three methods: (a) factoring (b) completing the square (c) using the quadratic equation formula.Factoring:25x2+20x+4 = 0(5+2)(5x+2) = 0Solution: x = -2/5 also x = -2/5 (they both have equal roots)
4 and the two equal roots are 2/5 and 2/5
Yes because if 1+0=1 than 0 plus b equals b
The equation you are looking for is x + 5 = 0. To solve for x, you would subtract 5 from both sides of the equation. This would give you x = -5. Therefore, -5 plus 5 equals 0.
A=0 b=0 c=0
No.
x = y = 0 ?
many solutions
0
It equals 7